C# 将十进制变量拆分为整数部分和分数部分
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Split decimal variable into integral and fraction parts
提问by invarbrass
I am trying to extract the integral and fractional parts from a decimal value (both parts should be integers):
我试图从十进制值中提取整数和小数部分（两个部分都应该是整数）：
decimal decimalValue = 12.34m;
int integral = (int) decimal.Truncate(decimalValue);
int fraction = (int) ((decimalValue - decimal.Truncate(decimalValue)) * 100);
(for my purpose, decimal variables will contain up to 2 decimal places)
（出于我的目的，十进制变量将包含最多 2 个小数位）
Are there any better ways to achieve this?
有没有更好的方法来实现这一目标？
回答by Barry Kaye
How about:
怎么样：
int fraction = (int) ((decimalValue - integral) * 100);
回答by SOReader
Try mathematical definition:
尝试数学定义：
var fraction = (int)(100.0m * (decimalValue - Math.Floor(decimalValue)));
Although, it is not better performance-wise but at least it works for negative numbers.
虽然，它在性能方面并不是更好，但至少它适用于负数。
回答by Girish Sakhare
decimal fraction = (decimal)2.78;
int iPart = (int)fraction;
decimal dPart = fraction % 1.0m;
回答by OMARY
decimal fraction = doubleNumber - Math.Floor(doubleNumber)
or something like that.
或类似的东西。
回答by Aamol
For taking out fraction you can use this solution:
要取出分数，您可以使用此解决方案：
Math.ceil(((f < 1.0) ? f : (f % Math.floor(f))) * 10000)
