C语言 C for 用指针循环遍历数组
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C for loop through array with pointers
提问by TutenStain
I'm new to C but I have experience in Java and Android. I have a problem in my for loop. It will never end and just go on and on.
我是 C 新手，但我有 Java 和 Android 方面的经验。我的 for 循环有问题。它永远不会结束，只会继续下去。
char entered_string[50];
char *p_string = NULL;
gets( entered_string );
for( p_string = entered_string; p_string != ' char str[] = "54321";
char *p;
p = str;
for (p; *p != '##代码##';++p)
{
printf("%s \n",p);
}
'; p_string++ ){
//....
}
I know that gets is unsafe, not recommended and deprecated but according to my specs I have to use it. I want to loop through each element by using pointers.
我知道 get 是不安全的，不推荐和弃用，但根据我的规范，我必须使用它。我想使用指针遍历每个元素。
回答by Cornstalks
Your test should be *p_string != '\0';
你的测试应该是 *p_string != '\0';
p_stringis a pointer, and your loop is checking if the pointer is != '\0'. You're interested in if the value is != '\0', and to get the value out of a pointer you have to dereference it with *.
p_string是一个指针，您的循环正在检查指针是否为!= '\0'. 您对值是否为 感兴趣!= '\0'，并且要从指针中获取值，您必须使用 取消引用它*。
回答by Diizzy
Output:
54321
4321
321
21
1
输出：
54321
4321
321
21
1
回答by Nikolai Fetissov
It should be *p_string != '\0'for the condition - you need to de-reference the pointer.
它应该是*p_string != '\0'针对条件的 - 您需要取消引用指针。
