php 在命令行执行一串PHP代码
声明：本页面是StackOverFlow热门问题的中英对照翻译，遵循CC BY-SA 4.0协议，如果您需要使用它，必须同样遵循CC BY-SA许可，注明原文地址和作者信息，同时你必须将它归于原作者（不是我）：StackOverFlow
原文地址: http://stackoverflow.com/questions/2954540/
Warning: these are provided under cc-by-sa 4.0 license. You are free to use/share it, But you must attribute it to the original authors (not me):
StackOverFlow
execute a string of PHP code on the command line
提问by Matthew J Morrison
I'd like to be able to run a line of PHP code on the command line similar to how the following options work:
我希望能够在命令行上运行一行 PHP 代码，类似于以下选项的工作方式：
:~> perl -e "print 'hi';"
:~> python -c "print 'hi'"
:~> ruby -e "puts 'hi'"
I'd like to be able to do:
我希望能够做到：
:~> php "echo 'hi';"
I've read that there is a -r option that can do what I need for php, however it doesn't appear to be available when I try to use it. I've tried using PHP 5.2.13 and PHP 4.4.9 and neither have an -r option available.
我读过有一个 -r 选项可以完成我对 php 的需求，但是当我尝试使用它时它似乎不可用。我试过使用 PHP 5.2.13 和 PHP 4.4.9，但都没有 -r 选项可用。
I wrote this script (that I called run_php.php) - which works, but I'm not a huge fan of it just because I feel like there should be a more "correct" way to do it.
我写了这个脚本（我称之为 run_php.php） - 它有效，但我不是它的忠实粉丝，因为我觉得应该有一个更“正确”的方法来做到这一点。
#!/usr/bin/php5 -q
<?php echo eval($argv[1]); ?>
My question is: is there a -r option? If so, why is it not available when I run --help? If there is no -r option, what is the best way to do this (without writing an intermediary script if possible)?
我的问题是：有 -r 选项吗？如果是这样，为什么在我运行 --help 时它不可用？如果没有 -r 选项，最好的方法是什么（如果可能，不编写中间脚本）？
Thanks!
谢谢！
=== EDIT ===
=== 编辑 ===
Because I don't think it was very clear above, the -r option is NOT available to me. Here is the php -h output for both versions of PHP that I'm running.
因为我认为上面不是很清楚，所以 -r 选项对我不可用。这是我正在运行的两个 PHP 版本的 php -h 输出。
PHP 4.4.9
PHP 4.4.9
Usage: php [-q] [-h] [-s] [-v] [-i] [-f <file>]
php <file> [args...]
-a Run interactively
-C Do not chdir to the script's directory
-c <path>|<file> Look for php.ini file in this directory
-n No php.ini file will be used
-d foo[=bar] Define INI entry foo with value 'bar'
-e Generate extended information for debugger/profiler
-f <file> Parse <file>. Implies `-q'
-h This help
-i PHP information
-l Syntax check only (lint)
-m Show compiled in modules
-q Quiet-mode. Suppress HTTP Header output.
-s Display colour syntax highlighted source.
-v Version number
-w Display source with stripped comments and whitespace.
-z <file> Load Zend extension <file>.
php 5.2.13
php 5.2.13
Usage: php [-q] [-h] [-s] [-v] [-i] [-f <file>]
php <file> [args...]
-a Run interactively
-C Do not chdir to the script's directory
-c <path>|<file> Look for php.ini file in this directory
-n No php.ini file will be used
-d foo[=bar] Define INI entry foo with value 'bar'
-e Generate extended information for debugger/profiler
-f <file> Parse <file>. Implies `-q'
-h This help
-i PHP information
-l Syntax check only (lint)
-m Show compiled in modules
-q Quiet-mode. Suppress HTTP Header output.
-s Display colour syntax highlighted source.
-v Version number
-w Display source with stripped comments and whitespace.
-z <file> Load Zend extension <file>.
There is NO -r option. When I try to use the -r option I get:
没有 -r 选项。当我尝试使用 -r 选项时，我得到：
Error in argument 1, char 2: option not found r
Sorry for the confusion.
对困惑感到抱歉。
回答by Artefacto
EDIT2: Yep, it's there in PHP 5.2's cli SAPI.
EDIT2：是的，它在PHP 5.2 的 cli SAPI 中。
EDIT: If you cannot upgrade and that's the case that there's no such option in PHP 5.2 (I don't have it at hand to test), you can do this:
编辑：如果您无法升级并且在 PHP 5.2 中没有这样的选项（我手头没有它来测试），您可以这样做：
glopes@nebm:~$ echo "<?php echo \"hi\n\";" | php hi
Original:
原来的：
There is indeed a -roption (though I'm not sure about PHP 5.2):
确实有一个-r选项（虽然我不确定 PHP 5.2）：
D:\>php -r "echo 'hi';"; hi
Just make sure you are using the command line version of PHP. php --versionshould give you something like this (notice "cli"):
只要确保您使用的是命令行版本的 PHP。php --version应该给你这样的东西（注意“cli”）：
D:\>php --version PHP 5.3.0 (cli) (built: May 20 2010 19:05:12) (DEBUG) Copyright (c) 1997-2009 The PHP Group Zend Engine v2.3.0, Copyright (c) 1998-2009 Zend Technologies
回答by Damian W.
In new versions of PHP you just type "php -a" and you hop into an interactive mode, where you can experiment with PHP.
在新版本的 PHP 中，您只需键入“php -a”并跳转到交互模式，您可以在其中试验 PHP。
回答by Sumoanand
Extra Semi colon is not required in the end.
最后不需要额外的分号。
You can mention php -r "echo 'hi';"instead of php -r "echo 'hi';";
你可以提到php -r "echo 'hi';"而不是php -r "echo 'hi';";
Another example(To get current timestamp at command line):
另一个例子（在命令行获取当前时间戳）：
php -r 'print time()."\n";'
回答by Benubird
The easiest way to do it is to use the -r flag. However, I've found that it does not allow multiline inputs. To work around that, you can do this:
最简单的方法是使用 -r 标志。但是，我发现它不允许多行输入。要解决此问题，您可以执行以下操作：
php -r "passthru(file_get_contents('php://stdin'));"
Which lets you pipe from stdin, like so:
它可以让你从标准输入管道，像这样：
echo -n "echo 'test';" | php -r "passthru(file_get_contents('php://stdin'));"
However, to answer the original question, if you do not have the -r flag available, it is also possible to use the -f flag - just pass stdin as the file to open: php -f /dev/stdin
但是，要回答原始问题，如果您没有可用的 -r 标志，也可以使用 -f 标志 - 只需将 stdin 作为要打开的文件传递： php -f /dev/stdin
If you do this, be aware that a) you need to include a blank space at the start of the input, and b) you have to open with <?php. Example:
如果您这样做，请注意 a) 您需要在输入的开头包含一个空格，并且 b) 您必须以<?php. 例子：
echo -ne " <?php\necho 'test';" | php -f /dev/stdin
回答by allnightgrocery
Take a look at this page on PHP command line features, if you haven't already. There are some posts on issues based on OS and double or single quotes.
如果您还没有，请查看有关PHP 命令行功能的页面。有一些关于基于操作系统和双引号或单引号的问题的帖子。
I would also check the PHP information
我也会检查PHP信息
php -i
php -i
to see if PHP was compiled with CLI support disabled(--disable-cli).
查看 PHP 是否是在禁用 CLI 支持的情况下编译的(--disable-cli)。
