php 将月份编号转换为月份简称
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Convert month number to month short name
提问by Elitmiar
I have a variable with the following value
我有一个具有以下值的变量
$month = 201002;
the first 4 numbers represent the year, and the last 2 numbers represent the month. I need to get the last 2 numbers in the month string name eg. Feb
前4个数字代表年份，后2个数字代表月份。我需要获取月份字符串名称中的最后 2 个数字，例如。二月
My code looks like this
我的代码看起来像这样
<?php echo date('M',substr($month,4,6)); ?>
I can I go about to obtain the month name
我可以去获取月份名称吗
回答by mexique1
Append "01" and strtotime will be able to parse the string :
附加“01”和 strtotime 将能够解析字符串：
echo date('M', strtotime($month . '01'));
回答by r3zn1k
回答by Gaurav Porwal
This may help you..
这可能会帮助你..
$month = substr($month, -2, 2);
echo date('M', strtotime(date('Y-'. $month .'-d')));
回答by Hossam Ghareeb
You can use the DateTime Class to get a Date data structure using date string and format. Then get a date string with any format like this:
您可以使用 DateTime 类来获取使用日期字符串和格式的日期数据结构。然后获取任何格式的日期字符串，如下所示：
$month = 201002;
$date = DateTime::createFromFormat('Yd', $month);
$monthName = $date->format('M'); // will get Month name
回答by OlimilOops
$mydate = "201002";
date('M', mktime(0, 0, 0, substr($mydate, 4, 2), 1, 2000));
回答by Your Common Sense
Being a programmer, and even knowing nothing of PHP data magic, I'd made it
作为一名程序员，甚至对 PHP 数据魔法一无所知，我做到了
$month = intval(substr($input_date,4,2));
$mons = explode(" ","Zer Jan Feb Mar Apr May Jun Jul Aug Sep Oct Nov Dec");
echo $mons[$month];
