复合唯一键验证 - laravel
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composite-unique-key-validation - laravel
提问by sumit
seems it's not possible with built-in validators, how I should implement this feature in the model?
内置验证器似乎不可能,我应该如何在模型中实现这个功能?
$rules = [
'user_id' => 'required|unique:service_details,user_id',
'service_id'=>'required|unique:service_details,service_id'
];
above will prevent duplicacy of user_id
and service_id
independently which is not my requirement
以上将防止重复user_id
和service_id
独立,这不是我的要求
it will reject
它会拒绝
(1,2)
(1,3)
because 1 is duplicate but it should be accepted as i want composite unique key
因为 1 是重复的,但它应该被接受,因为我想要复合唯一键
回答by harryg
Composite unique field validation is provided out-of-the-box in 5.0+. I can't speak for earlier versions.
复合唯一字段验证在 5.0+ 中开箱即用。我不能说早期版本。
You can essentially specify a where clause for when your unique validation rule applies. E.g.
您基本上可以为何时应用您的唯一验证规则指定一个 where 子句。例如
'term' => 'unique:terms,term,NULL,id,taxonomy,category'
This rule says that term
should be unique on the terms
table but only where the taxonomy
is equal to "category".
这条规则说term
在terms
表上应该是唯一的,但只有在taxonomy
等于“类别”的地方。
For example, it will prevent a "news" category being duplicated but I can still have a "news" tag.
例如,它会防止重复“新闻”类别,但我仍然可以拥有“新闻”标签。
I don't know your schema but in your case it'd be something like this:
我不知道你的架构,但在你的情况下,它会是这样的:
$user_id = Request::get('user_id', $default);
$service_id = Request::get('service_id', $default);
// or another way of specifying the accompanying service/user ID for the where clauses
$rules = [
'user_id' => 'unique:service_details,user_id,NULL,id,service_id,' . $service_id;
'service_id' => 'unique:service_details,service_id,NULL,id,user_id,' . $user_id;
];
回答by nozzleman
This is not possible out of the box in Laravel. You would either have to write a custom validatoror use a package for that.
这在 Laravel 中开箱即用是不可能的。您要么必须编写自定义验证器,要么为此使用包。
Here is one that should do what you need: - https://github.com/felixkiss/uniquewith-validator
这是一个应该做你需要的: - https://github.com/felixkiss/uniquewith-validator
With this package, your rules could look like the following:
使用此包,您的规则可能如下所示:
$rules = array(
'user_id' => 'required|unique_with:service_details,service_id',
'service_id' => 'required',
);
It works for both Laravel 4 and 5.
它适用于 Laravel 4 和 5。
回答by ErcanE
My solution
我的解决方案
Laravel 5.3 and 5.4
Laravel 5.3 和 5.4
Note: Without model binding
注意:无模型绑定
Store
店铺
'required',
Rule::unique('service_details','service_id')->where(function ($query) {
$query->where('user_id', $this->request->get('user_id'));
})
Update
更新
'required',
Rule::unique('service_details','service_id')->ignore($this->route()->id)->where(function ($query) {
$query->where('user_id', $this->request->get('user_id'));
})
回答by s vinayagam
With the help of this link, I am able to achieve composite validation from out of the box laravel 5.3. I knew it is old question and answered already. In my case vendor and client combination is unique.
在此链接的帮助下,我能够从开箱即用的 laravel 5.3 中实现复合验证。我知道这是个老问题并且已经回答了。就我而言,供应商和客户的组合是独一无二的。
My sample code is below
我的示例代码如下
$this->validate($request, [
'Vendor'=> 'bail|required|int',
'Client'=> 'bail|required|int',
'discount'=> 'required|numeric',
'Client'=>'unique:billings,client_id,vendor_id'.$request->Vendor
]);