java 在 RESTful Web 服务中使用多个资源
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Consume multiple resources in a RESTful Web Service
提问by Arthur Eirich
In my web server application I have a method, which modifies an xml document and looks similar to that:
在我的 web 服务器应用程序中,我有一个方法,它修改一个 xml 文档,看起来类似于:
@POST
@Path("somePath")
@Consumes({"application/xml", "application/zip"})
public Response modifyXml() {
//some processing
}
The consumed zip archive contains the xml file which needs to be modified and some other files. How can I distinguish between consumed xml file and the archive inside the method and which kind of method parameter should I use to represent this consumed resource?
使用的 zip 存档包含需要修改的 xml 文件和一些其他文件。如何区分消耗的 xml 文件和方法内的存档,以及我应该使用哪种方法参数来表示这个消耗的资源?
采纳答案by Paul Samsotha
One solution is to just read from an InputStream
. You could wrap the InputStream
in a ZipInputStream
. With ZipInputStream
you can get a ZipEntry
with ZipInputStream.getNextEntry()
, then you can get the file name with ZipEntry.getName()
. Then just check if the name endsWith(".xml")
.
一种解决方案是仅从InputStream
. 你可以在包裹InputStream
中ZipInputStream
。WithZipInputStream
你可以得到一个ZipEntry
with ZipInputStream.getNextEntry()
,然后你可以得到文件名 with ZipEntry.getName()
。然后只需检查名称endsWith(".xml")
。
With this though, you would need to consume application/octet-stream
. Here's a simple example
尽管如此,你需要消耗application/octet-stream
. 这是一个简单的例子
@Path("/zip")
public class ZipResource {
@POST
@Consumes(MediaType.APPLICATION_OCTET_STREAM)
public Response postZipFile(InputStream is) throws Exception {
StringBuilder builder;
try (ZipInputStream zip = new ZipInputStream(is)) {
builder = new StringBuilder("==== Data ====\n");
ZipEntry entry;
while ((entry = zip.getNextEntry()) != null) {
String filename = entry.getName();
if (filename.endsWith(".xml")) {
builder.append("name: ").append(entry.getName()).append("\n");
String xml = filePartToString(zip, (int) entry.getSize());
builder.append("data: ").append(xml).append("\n");
}
zip.closeEntry();
}
}
return Response.ok(builder.toString()).build();
}
private String filePartToString(InputStream is, int size) throws Exception {
String xml;
byte[] buff = new byte[size];
is.read(buff, 0, size);
return new String(buff);
}
}
Here's a test
这是一个测试
@Test
public void testResteasy() throws Exception {
WebTarget target = client.target(
TestPortProvider.generateURL(BASE_URI)).path("zip");
File file = new File("C:/test/test.zip");
Response response = target.request().post(
Entity.entity(file, MediaType.APPLICATION_OCTET_STREAM));
System.out.println(response.getStatus());
System.out.println(response.readEntity(String.class));
response.close();
}
Using these files in a zip
在 zip 中使用这些文件
test1.xml
---------
<test1>hello world</test1>
test2.xml
---------
<test2>hello squirrel</test2>
test3.json
----------
{
"test3":"Hello Girls"
}
I get the following result
我得到以下结果
==== Data ====
name: test1.xml
data: <test1>hello world</test1>
name: test2.xml
data: <test2>hello squirrel</test2>
As an aside, if you have control over how the data is sent, you might want to also look into a multipart solution. There you set content types, and you can name each part, where they're easier to access.
顺便说一句,如果您可以控制数据的发送方式,您可能还想研究多部分解决方案。在那里您可以设置内容类型,您可以命名每个部分,以便更容易访问。
You can see Resteasy's support for multipart here, and the required dependency.
您可以在此处查看 Resteasy 对 multipart 的支持以及所需的依赖项。
UPDATE
更新
If you mustuse application/zip
, there is no standard support for this. So you would need to whip up your own MessageBodyReader
. It could be something as simple as wrapping and return the already provided InputStream
如果您必须使用application/zip
,则没有对此的标准支持。所以你需要掀起你自己的MessageBodyReader
. 它可以像包装并返回已经提供的一样简单InputStream
@Provider
@Consumes("application/zip")
public class ZipMessageBodyReader implements MessageBodyReader<ZipInputStream> {
@Override
public boolean isReadable(Class<?> type, Type genericType,
Annotation[] annotations, MediaType mediaType) {
return type == ZipInputStream.class;
}
@Override
public ZipInputStream readFrom(Class<ZipInputStream> type,
Type genericType, Annotation[] annotations, MediaType mediaType,
MultivaluedMap<String, String> httpHeaders,
InputStream entityStream) throws IOException, WebApplicationException {
return new ZipInputStream(entityStream);
}
}
Then in your resource method, you could just have a ZipInputStream
parameter, instead of InputStream
.
然后在您的资源方法中,您可以只有一个ZipInputStream
参数,而不是InputStream
.
@POST
@Consumes("application/zip")
public Response postZipFile(ZipInputStream zip) throws Exception {
On the client side (with the client API), if you were to use application/zip
, you would of course need to also write a MessageBodyWriter
for application/zip
在客户端(使用客户端 API),如果要使用application/zip
,当然还需要编写一个MessageBodyWriter
forapplication/zip
UPDATE 2
更新 2
From Comment:I need my method to be able to consume both a simple xml file and a zip archive which contains the xml file, so I annotate the method something like (pseudo code): "consumes(xml, zip)" and declare a method with the parameter InputStream is; In the method body I then need to determine whether this InputStream is of type xml or a zip archive and want to write something similar to: "if(is of type xml) {then treat is as an xml} else {treat is as a zip archive}. Hopefully now the question is more understandable
来自评论:我需要我的方法能够同时使用一个简单的 xml 文件和一个包含 xml 文件的 zip 存档,所以我对该方法进行了注释(伪代码):“consumes(xml, zip)”并声明一个带有参数 InputStream 的方法是;然后在方法主体中,我需要确定此 InputStream 是 xml 类型还是 zip 存档,并希望编写类似于以下内容的内容:“if(is of type xml) {then Treat is as an xml} else {treat is as a zip 存档}。希望现在这个问题更容易理解了
We can keep your original method signature accepting both application/xml
and application/zip
. Also we can check which on is actually being sent by injecting HttpHeaders
and getting the Content-Type
from it. Base on that, we will determine how to extract. Here's another example of how we can complete this
我们可以保留您的原始方法签名同时接受application/xml
和application/zip
。我们还可以通过注入HttpHeaders
并Content-Type
从中获取来检查实际发送的是哪个。在此基础上,我们将确定如何提取。这是我们如何完成此操作的另一个示例
@Path("/zip")
public class ZipResource {
@POST
@Consumes({"application/zip", "application/xml"})
public Response postZipFile(InputStream is, @Context HttpHeaders headers) throws Exception {
String contentType = headers.getHeaderString(HttpHeaders.CONTENT_TYPE);
String returnString = null;
if (null != contentType) switch (contentType) {
case "application/xml":
returnString = readXmlFile(is);
break;
case "application/zip":
returnString = readZipFile(is);
break;
}
return Response.ok(returnString).build();
}
private String filePartToString(InputStream is, int size) throws Exception {
String xml;
byte[] buff = new byte[size];
is.read(buff, 0, size);
return new String(buff);
}
private String readXmlFile(InputStream is) {
StringWriter writer = new StringWriter();
try {
IOUtils.copy(is, writer, "utf-8");
} catch (IOException ex) {
Logger.getLogger(ZipResource.class.getName()).log(Level.SEVERE, null, ex);
}
return writer.toString();
}
private String readZipFile(InputStream is) {
StringBuilder builder = new StringBuilder("==== Data ====\n");
try (ZipInputStream zip = new ZipInputStream(is)) {
ZipEntry entry;
while ((entry = zip.getNextEntry()) != null) {
String filename = entry.getName();
if (filename.endsWith(".xml")) {
builder.append("name: ").append(entry.getName()).append("\n");
String xml = filePartToString(zip, (int) entry.getSize());
builder.append("data: ").append(xml).append("\n");
}
zip.closeEntry();
}
} catch (Exception ex) {
ex.printStackTrace();
}
return builder.toString();
}
}
We would need a MessageBodyReader
to handle the application/zip
type. The one above works fine, but we just need to it return an InputStream
instead of ZipInputStream
我们需要一个MessageBodyReader
来处理application/zip
类型。上面的工作正常,但我们只需要它返回一个InputStream
而不是ZipInputStream
@Provider
@Consumes("application/zip")
public class ZipMessageBodyReader implements MessageBodyReader<InputStream> {
@Override
public boolean isReadable(Class<?> type, Type genericType,
Annotation[] annotations, MediaType mediaType) {
return type == InputStream.class;
}
@Override
public InputStream readFrom(Class<InputStream> type,
Type genericType, Annotation[] annotations, MediaType mediaType,
MultivaluedMap<String, String> httpHeaders,
InputStream entityStream) throws IOException, WebApplicationException {
return entityStream;
}
}
Now with the test
现在通过测试
@Test
public void testResteasy() throws Exception {
WebTarget target = client.target(
TestPortProvider.generateURL(BASE_URI)).path("zip");
File file = new File("C:/test/test.zip");
Response response = target.request().post(
Entity.entity(file, "application/zip"));
System.out.println(response.getStatus());
System.out.println(response.readEntity(String.class));
response.close();
file = new File("C:/test/test1.xml");
response = target.request().post(
Entity.entity(file, "application/xml"));
System.out.println(response.getStatus());
System.out.println(response.readEntity(String.class));
response.close();
}
we get the following
我们得到以下
200
==== Data ====
name: test1.xml
data: <test1>hello world</test1>
name: test2.xml
data: <test2>hello squirrel</test2>
200
<test1>hello world</test1>
Note:With the client, I had to implement a MessageBodyWriter
to handle the application/zip
type. The following is a simple implementation just to get the test to work. A real implementation would need some fixing
注意:对于客户端,我必须实现一个MessageBodyWriter
来处理application/zip
类型。下面是一个简单的实现,只是为了让测试工作。真正的实现需要一些修复
@Provider
@Produces("application/xml")
public class ZipClientMessageBodyWriter implements MessageBodyWriter<File> {
@Override
public boolean isWriteable(Class<?> type, Type genericType,
Annotation[] annotations, MediaType mediaType) {
return type == File.class;
}
@Override
public long getSize(File t, Class<?> type, Type genericType,
Annotation[] annotations, MediaType mediaType) {
return -1;
}
@Override
public void writeTo(File t, Class<?> type, Type genericType,
Annotation[] annotations, MediaType mediaType,
MultivaluedMap<String, Object> httpHeaders, OutputStream entityStream)
throws IOException, WebApplicationException {
IOUtils.write(IOUtils.toByteArray(new FileInputStream(t)), entityStream);
}
}
....
client.register(ZipClientMessageBodyWriter.class);
You'll also note in some of the example code, I made use of Apache Commons IOUtils
. Excuse me for that. I was being lazy :-)
您还会在一些示例代码中注意到,我使用了 Apache Commons IOUtils
。对不起。我很懒:-)
UPDATE 3
更新 3
Actually, we don't need to MessageBodyReader
. The algorithm to find the reader will actually just default to the InputStream
reader, as it supports application/xml
, so it will already return the InputStream
whether we have a reader for the application/zip
or not
实际上,我们不需要MessageBodyReader
。找到读者的算法其实只是默认为InputStream
读者,因为它支持application/xml
,所以它会已经返回InputStream
我们是否有对读者application/zip
还是不