ios 子串在 NSString 中的位置
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Position of a Substring in NSString
提问by Shaheen Rehman
How I can get the position/Index of a substring within an NSString?
如何获取NSString?中子字符串的位置/索引？
I am finding the location in the following way.
我正在通过以下方式找到位置。
NSRange range = [string rangeOfString:searchKeyword];
NSLog (@"match found at index:%u", range.location);
This returns index:2147483647when searchKeywordis a substring within string.
这将返回index:2147483647whensearchKeyword是 中的子字符串string。
How i can get the index value like 20or 5like that?
我如何获得类似20或5类似的索引值？
回答by Lily Ballard
2147483647is the same thing as NSNotFound, which means the string you searched for (searchKeyword) wasn't found.
2147483647与 相同NSNotFound，这意味着searchKeyword未找到您搜索的字符串 ( )。
NSRange range = [string rangeOfString:searchKeyword];
if (range.location == NSNotFound) {
NSLog(@"string was not found");
} else {
NSLog(@"position %lu", (unsigned long)range.location);
}
回答by Abhishek
NSString *searchKeyword = @"your string";
NSRange rangeOfYourString = [string rangeOfString:searchKeyword];
if(rangeOfYourString.location == NSNotFound)
{
// error condition — the text searchKeyword wasn't in 'string'
}
else{
NSLog(@"range position %lu", rangeOfYourString.location);
}
NSString *subString = [string substringToIndex:rangeOfYourString.location];
may this will help you....
可能这将帮助你....
