给 777 权限以在 php 中动态创建文件
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Give 777 permission to dynamically created file in php
提问by Rohit Goel
Hi i have a script which dynamicallycreated a file on my local directory Please tell me how can i give 777 permission to that file right now it is unaccessible in the browser
嗨，我有一个脚本，它在我的本地目录上动态创建了一个文件 请告诉我我现在如何为该文件授予 777 权限，它在浏览器中无法访问
<?php
//Get the file
$content = 'http://xxx.xxx.com.mx/media/catalog/product/cache/1/image/9df78eab33525d08d6e5fb8d27136e95/b/r/bridal-shoes1.jpg ';
$content1 = explode('/', $content);
$end = end($content1);
echo $end;
//print_r($content1[12]);
//Store in the filesystem.
$my_file = $end;
$handle = fopen($my_file, 'w') or die('Cannot open file: '.$my_file); //implicitly creates file
$path = '/var/www/'.$end;
copy($content, $path);
?>
回答by Alessandro Minoccheri
回答by Elton da Costa
use:
用：
private function writeFileContent($file, $content){
$fp = fopen($file, 'w');
fwrite($fp, $content);
fclose($fp);
chmod($file, 0777); //changed to add the zero
return true;
}
回答by Hiren Makwana
Give permission in to dynamically created file
授予动态创建文件的权限
$upPath = yourpath;
if(!file_exists($upPath))
{
$oldmask = umask(0);
mkdir($upPath, 0777, true);
umask($oldmask);
}
回答by Thomas Clayson
回答by SameerJ
set default permissionto u r directory (i.e rwx) using setfacl command
设置default permission为您的目录（即rwx）使用setfacl command
ex: setfacl -d -m o::rwx your/directory/path
then any thing u create in that directory it takes rwxpermission.
然后您在该目录中创建的任何内容都需要rwx许可。
回答by Rohit Goel
we can evenignore *$handle*it will still createthe fileand copythe content to the $path
我们可以甚至忽略 * $处理*它仍然会创建的文件和复制内容到 $ PATH
<?php
//Get the file
$content = 'http://dev.aviesta.com.mx/media/catalog/product/cache/1/image/9df78eab33525d08d6e5fb8d27136e95/b/r/bridal-shoes1.jpg ';
$content1 = explode('/', $content);
$end = end($content1);
echo $end;
//print_r($content1[12]);
//Store in the filesystem.
$my_file = $end;
$handle = fopen($my_file, 'w') or die('Cannot open file: '.$my_file); //implicitly creates file
$path = '/var/www/'.$end;
copy($content, $path);
?>
