PHP 获取给定目录的所有子目录

PHP Get all subdirectories of a given directory

提问by Adrian M.

How can I get all sub-directories of a given directory without files, .(current directory) or ..(parent directory) and then use each directory in a function?

如何在没有文件.（当前目录）或..（父目录）的情况下获取给定目录的所有子目录，然后在函数中使用每个目录？

回答by ghostdog74

you can use glob()with GLOB_ONLYDIRoption

您可以将glob()与GLOB_ONLYDIR选项一起使用

or

或者

$dirs = array_filter(glob('*'), 'is_dir');
print_r( $dirs);

回答by Coreus

Here is how you can retrieve only directories with GLOB:

以下是如何使用 GLOB 仅检索目录：

$directories = glob($somePath . '/*' , GLOB_ONLYDIR);

回答by stloc

The Spl DirectoryIteratorclass provides a simple interface for viewing the contents of filesystem directories.

Spl DirectoryIterator类提供了一个用于查看文件系统目录内容的简单界面。

$dir = new DirectoryIterator($path);
foreach ($dir as $fileinfo) {
    if ($fileinfo->isDir() && !$fileinfo->isDot()) {
        echo $fileinfo->getFilename().'<br>';
    }
}

回答by Gordon

Almost the same as in your previous question:

与您之前的问题几乎相同：

$iterator = new RecursiveIteratorIterator(
                new RecursiveDirectoryIterator($yourStartingPath), 
            RecursiveIteratorIterator::SELF_FIRST);

foreach($iterator as $file) {
    if($file->isDir()) {
        echo strtoupper($file->getRealpath()), PHP_EOL;
    }
}

Replace strtoupperwith your desired function.

替换strtoupper为您想要的功能。

回答by keyur0517

Try this code:

试试这个代码：

<?php
$path = '/var/www/html/project/somefolder';

$dirs = array();

// directory handle
$dir = dir($path);

while (false !== ($entry = $dir->read())) {
    if ($entry != '.' && $entry != '..') {
       if (is_dir($path . '/' .$entry)) {
            $dirs[] = $entry; 
       }
    }
}

echo "<pre>"; print_r($dirs); exit;

回答by Ricardo Canelas

In Array:

在数组中：

function expandDirectoriesMatrix($base_dir, $level = 0) {
    $directories = array();
    foreach(scandir($base_dir) as $file) {
        if($file == '.' || $file == '..') continue;
        $dir = $base_dir.DIRECTORY_SEPARATOR.$file;
        if(is_dir($dir)) {
            $directories[]= array(
                    'level' => $level
                    'name' => $file,
                    'path' => $dir,
                    'children' => expandDirectoriesMatrix($dir, $level +1)
            );
        }
    }
    return $directories;
}

//access:

//使用权：

$dir = '/var/www/';
$directories = expandDirectoriesMatrix($dir);

echo $directories[0]['level']                // 0
echo $directories[0]['name']                 // pathA
echo $directories[0]['path']                 // /var/www/pathA
echo $directories[0]['children'][0]['name']  // subPathA1
echo $directories[0]['children'][0]['level'] // 1
echo $directories[0]['children'][1]['name']  // subPathA2
echo $directories[0]['children'][1]['level'] // 1

Example to show all:

显示所有示例：

function showDirectories($list, $parent = array())
{
    foreach ($list as $directory){
        $parent_name = count($parent) ? " parent: ({$parent['name']}" : '';
        $prefix = str_repeat('-', $directory['level']);
        echo "$prefix {$directory['name']} $parent_name <br/>";  // <-----------
        if(count($directory['children'])){
            // list the children directories
            showDirectories($directory['children'], $directory);
        }
    }
}

showDirectories($directories);

// pathA
// - subPathA1 (parent: pathA)
// -- subsubPathA11 (parent: subPathA1)
// - subPathA2 
// pathB
// pathC

回答by Sanaan Barzinji

<?php
    /*this will do what you asked for, it only returns the subdirectory names in a given
      path, and you can make hyperlinks and use them:
    */

    $yourStartingPath = "photos\";
    $iterator = new RecursiveIteratorIterator( 
        new RecursiveDirectoryIterator($yourStartingPath),  
        RecursiveIteratorIterator::SELF_FIRST);

    foreach($iterator as $file) { 
        if($file->isDir()) { 
            $path = strtoupper($file->getRealpath()) ; 
            $path2 = PHP_EOL;
            $path3 = $path.$path2;

            $result = end(explode('/', $path3)); 

            echo "<br />". basename($result );
        } 
    } 

    /* best regards,
        Sanaan Barzinji
        Erbil
    */
?>

回答by Macbric

Proper way

合适的方式

/**
 * Get all of the directories within a given directory.
 *
 * @param  string  $directory
 * @return array
 */
function directories($directory)
{
    $glob = glob($directory . '/*');

    if($glob === false)
    {
        return array();
    }

    return array_filter($glob, function($dir) {
        return is_dir($dir);
    });
}

Inspired by Laravel

灵感来自 Laravel

回答by Jan-Fokke

You can try this function (PHP 7 required)

你可以试试这个功能（需要PHP 7）

function getDirectories(string $path) : array
{
    $directories = [];
    $items = scandir($path);
    foreach ($items as $item) {
        if($item == '..' || $item == '.')
            continue;
        if(is_dir($path.'/'.$item))
            $directories[] = $item;
    }
    return $directories;
}

回答by Sultan

This is the one liner code:

这是单行代码：

 $sub_directories = array_map('basename', glob($directory_path . '/*', GLOB_ONLYDIR));