javascript 如何将参数传递给 jQuery 插件
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How to pass parameter to a jQuery plugin
提问by eepp
I have a question which at the first glance might seem to be stupid. I got problem figuring it out and whenever I use it, nothing really happens. I have a plugin in jQuery written by myself which is like this:
我有一个乍一看似乎很愚蠢的问题。我在弄清楚它时遇到了问题，每当我使用它时，什么都没有发生。我有一个自己编写的jQuery插件，如下所示：
(function(){
$.fn.myPlugin = function(options){
var options = $.extend({
firstParameter : null;
}
// the rest of the plugin
})(jQuery)
But when I call it from an HTML file, like this: ("#object").myPlugin(2);, it fails to work (note the parameter that I have passed). But if I skip the argument and call it like this: ("#object").myPlugin();, it all works. What is the problem?
但是当我从 HTML 文件调用它时，像这样: ("#object").myPlugin(2);，它无法工作（注意我传递的参数）。但是，如果我跳过参数并像这样调用它：("#object").myPlugin();，一切都有效。问题是什么？
Thanks in advance
提前致谢
回答by eepp
You want this:
你要这个：
(function($) {
$.fn.extend({
myPlugin: function(options) {
var defaults = {
something: 23,
otherThing: 'hello'
};
options = $.extend(defaults, options);
console.log(options.something);
console.log(options.otherThing);
}
});
})(jQuery);
Now this should work to override the somethingoption (don't forget to pass an object):
现在这应该可以覆盖something选项（不要忘记传递一个对象）：
$('#object').myPlugin({something: 17});
回答by simpletron
You define a function with no parameter function() {} then you pass the jQuery to it. It may be the cause of problem.
您定义了一个没有参数 function() {} 的函数，然后将 jQuery 传递给它。这可能是问题的原因。
(function(){
// nothing is the $ here
$.fn.myPlugin = function(options){
var options = $.extend({
firstParameter : null;
}
// the rest of the plugin
})(jQuery)
You should change to
你应该改为
(function($) {})(jQuery)
and I think it will work. Hope this help
我认为它会起作用。希望这有帮助
