Spring 3 匹配通配符严格,但找不到元素'jee:jndi-lookup'的声明

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时间:2020-09-08 05:09:43  来源:igfitidea点击:

Spring 3 The matching wildcard is strict, but no declaration can be found for element 'jee:jndi-lookup'

springhibernatedb2jndi

提问by Hymanie

So I am having an issue similar to here...

所以我有一个类似于这里的问题......

Spring 3.0 Error: The matching wildcard is strict, but no declaration can be found for element

Spring 3.0 错误:匹配的通配符是严格的,但找不到元素的声明

my pom looks like this

我的 pom 看起来像这样

<beans xmlns="http://www.springframework.org/schema/beans" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xmlns:context="http://www.springframework.org/schema/context" xmlns:aop="http://www.springframework.org/schema/aop"
xmlns:p="http://www.springframework.org/schema/p" xmlns:mvc="http://www.springframework.org/schema/mvc"
xmlns:tx="http://www.springframework.org/schema/tx"
xmlns:jee="http://www.springframework.org/schema/jee"
xsi:schemaLocation="http://www.springframework.org/schema/beans
      http://www.springframework.org/schema/beans/spring-beans-3.0.xsd
      http://www.springframework.org/schema/mvc http://www.springframework.org/schema/mvc/spring-mvc-3.0.xsd
      http://www.springframework.org/schema/context http://www.springframework.org/schema/context/spring-context-3.0.xsd
      http://www.springframework.org/schema/aop http://www.springframework.org/schema/aop/spring-aop-3.0.xsd
      http://www.springframework.org/schema/tx http://www.springframework.org/schema/tx/spring-tx.xsd
      http://www.springframework.org/schema/jee/spring-jee-2.5.xsd">
...
<jee:jndi-lookup id="dataSource" jndi-name="jdbc/db" resource-ref="true" />

But when I try to run the service on Websphere I get the following...

但是当我尝试在 Websphere 上运行该服务时,我得到以下信息...

Line 16 in XML document from ServletContext resource [/WEB-INF/context/loyalty-servlet.xml] is invalid; nested exception is org.xml.sax.SAXParseException: cvc-complex-type.2.4.c: The matching wildcard is strict, but no declaration can be found for element 'jee:jndi-lookup'.

It seems this is different from my link because I already have the schema in the namespace. Any ideas?

这似乎与我的链接不同,因为我已经在命名空间中拥有架构。有任何想法吗?

回答by axtavt

Note the pattern of other items in xsi:schemaLocation- each namespace URI from xmlns:*attribute should be followed by its respective XSD location:

请注意中其他项目的模式xsi:schemaLocation- 来自xmlns:*属性的每个名称空间 URI应后跟其各自的 XSD 位置:

 xsi:schemaLocation="
     http://www.springframework.org/schema/beans 
     http://www.springframework.org/schema/beans/spring-beans-3.0.xsd       
     http://www.springframework.org/schema/mvc 
     http://www.springframework.org/schema/mvc/spring-mvc-3.0.xsd
     http://www.springframework.org/schema/context 
     http://www.springframework.org/schema/context/spring-context-3.0.xsd        
     http://www.springframework.org/schema/aop 
     http://www.springframework.org/schema/aop/spring-aop-3.0.xsd       
     http://www.springframework.org/schema/tx 
     http://www.springframework.org/schema/tx/spring-tx.xsd       
     http://www.springframework.org/schema/jee
     http://www.springframework.org/schema/jee/spring-jee-2.5.xsd">