python JSON 对象必须是 str、bytes 或 bytearray，而不是 'dict
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python JSON object must be str, bytes or bytearray, not 'dict
提问by dila93
In Python 3, to load json previously saved like this:
在 Python 3 中，要加载以前保存的 json，如下所示：
json.dumps(dictionary)
json.dumps(dictionary)
the output is something like
输出是这样的
{"('Hello',)": 6, "('Hi',)": 5}
{"('Hello',)": 6, "('Hi',)": 5}
when I use
当我使用
json.loads({"('Hello',)": 6, "('Hi',)": 5})
json.loads({"('Hello',)": 6, "('Hi',)": 5})
it doesn't works, this happens:
它不起作用，发生这种情况：
TypeError: the JSON object must be str, bytes or bytearray, not 'dict'
类型错误：JSON 对象必须是 str、bytes 或 bytearray，而不是 'dict'
回答by barak manos
json.loadstake a string as input and returns a dictionary as output.
json.loads将一个字符串作为输入并返回一个字典作为输出。
json.dumpstake a dictionary as input and returns a string as output.
json.dumps以字典作为输入并返回一个字符串作为输出。
With json.loads({"('Hello',)": 6, "('Hi',)": 5}),
与json.loads({"('Hello',)": 6, "('Hi',)": 5}),
You are calling json.loadswith a dictionary as input.
您正在json.loads使用字典作为输入进行调用。
You can fix it as follows (though I'm not quite sure what's the point of that):
您可以按如下方式修复它（尽管我不太确定这有什么意义）：
d1 = {"('Hello',)": 6, "('Hi',)": 5}
s1 = json.dumps(d1)
d2 = json.loads(s1)
回答by Mark Reed
You are passing a dictionary to a function that expects a string.
您正在将字典传递给需要字符串的函数。
This syntax:
此语法：
{"('Hello',)": 6, "('Hi',)": 5}
is both a valid Python dictionary literal and a valid JSON object literal. But loadsdoesn't take a dictionary; it takes a string, which it then interprets as JSON and returns the result asa dictionary (or string or array or number, depending on the JSON, but usually a dictionary).
既是有效的 Python 字典字面量又是有效的 JSON 对象字面量。但loads不带字典；它接受一个字符串，然后将其解释为 JSON 并将结果作为字典（或字符串、数组或数字，取决于 JSON，但通常是字典）返回。
If you pass this string to loads:
如果您将此字符串传递给loads：
'''{"('Hello',)": 6, "('Hi',)": 5}'''
then it will return a dictionary that looks a lot like the one you are trying to pass to it.
然后它会返回一个看起来很像你试图传递给它的字典。
You could also exploit the similarity of JSON object literals to Python dictionary literals by doing this:
您还可以通过执行以下操作来利用 JSON 对象文字与 Python 字典文字的相似性：
json.loads(str({"('Hello',)": 6, "('Hi',)": 5}))
But in either case you would just get back the dictionary that you're passing in, so I'm not sure what it would accomplish. What's your goal?
但是在任何一种情况下，您都只会取回您传入的字典，所以我不确定它会完成什么。你的目标是什么？
回答by Laxman Jeergal
import json
data = json.load(open('/Users/laxmanjeergal/Desktop/json.json'))
jtopy=json.dumps(data) #json.dumps take a dictionary as input and returns a string as output.
dict_json=json.loads(jtopy) # json.loads take a string as input and returns a dictionary as output.
print(dict_json["shipments"])
