php Laravel 中 HTML::link 的 URLEncode
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URLEncode for HTML::link in Laravel
提问by NightMICU
I am setting up a blog in Laravel and cannot seem to figure out how to generate escaped URLs with HTML::link(..). For example, I have links to different categories in the Blog such as Department News, I am trying to get a link formatted like so - http://localhost/blog/category/department+news., where Department Newsis generated by $post->category
我正在 Laravel 中建立一个博客，但似乎无法弄清楚如何使用HTML::link(..). 例如，我有指向博客中不同类别的链接，例如部门新闻，我试图获得一个格式如下的链接 - http://localhost/blog/category/department+news.，其中Department News由$post->category
I have tried the following code and it produces http://localhost/blog/Department News
我试过下面的代码，它产生 http://localhost/blog/Department News
{{ HTML::link('admin/blog/category/' . $post->category, $post->category) }}
How can I escape this and generate the desired URL?
我该如何转义并生成所需的 URL？
回答by Wesley Murch
Usually, you'd have each post category use a slugcolumn in the database for the URL fragment, and then use something like:
通常，您会让每个帖子类别使用slug数据库中的一列作为 URL 片段，然后使用类似的内容：
HTML::link('blog/category/'.$post->category->slug, $post->category->name)
There's appears to be no way with Laravel to automatically encode only certain parts of the URL, so you'd have to do it yourself:
Laravel 似乎无法仅对 URL 的某些部分进行自动编码，因此您必须自己进行编码：
HTML::link(
'admin/blog/category/'.urlencode(strtolower($post->category)),
$post->category
)
You might want to consider using the "slug" approach. You don't necessarily have to store it in the database, you could have your class generate it on the fly:
您可能需要考虑使用“slug”方法。您不必将它存储在数据库中，您可以让您的类动态生成它：
class Category {
function slug() {
return urlencode(strtolower($this->name));
}
}
I'm not sure what you're working with exactly, but hopefully you get the idea.
我不确定你在做什么，但希望你能明白。
回答by Artistan
Sorry. I disagree with Wesley, this works...
对不起。我不同意韦斯利，这有效......
If you used named routesthe Url::route('category_browse',[category])call will encode the values. The second parameter in the route method allows mixed content. So if you have only one parameter in your route you can pass a single value, otherwise an array.
如果您使用命名路由，则Url::route('category_browse',[category])调用将对值进行编码。route 方法中的第二个参数允许混合内容。因此，如果您的路由中只有一个参数，则可以传递一个值，否则传递一个数组。
in twig (TwigBridge) this is ...
在树枝（TwigBridge）中，这是......
{{ url_route('category_browse',[category]) }}
otherwise (Blade) it should be ...
否则（刀片）它应该是......
{{ Url::route('category_browse',[category]) }}
and your names route should be like this ...
你的名字路线应该是这样的......
Route::any('/blog/category/{category}',
array(
/*'before'=>'auth_check', -- maybe add a pre-filter */
'uses' =>'BlogController@category',
'as' => 'category_browse'
)
);
