java 如何使用Java将数据插入到mysql中

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时间:2020-10-31 10:06:05  来源:igfitidea点击:

How to insert data into mysql using Java

javamysql

提问by black_belt

I am trying to insert data into mysql database using Java. I am using the following code to fetch data from database and it is working fine.

我正在尝试使用 Java 将数据插入 mysql 数据库。我正在使用以下代码从数据库中获取数据,并且工作正常。

import java.sql.Connection;
import java.sql.DriverManager;
import java.sql.PreparedStatement;
import java.sql.ResultSet;

public class DbTest {

public static void main (String[] args) throws Exception{


    // Accessing Driver From Jar File
    Class.forName("com.mysql.jdbc.Driver");

    //DB Connection
    Connection con = DriverManager.getConnection("jdbc:mysql://localhost:3306/test","root","");  

    // MySQL Query
    PreparedStatement statement= con.prepareStatement("SELECT * FROM jam WHERE id='1'");

    //Creating Variable to execute query
    ResultSet result=statement.executeQuery();

    while(result.next()){

        System.out.println(result.getString(2));

    }

  }


  }

To Insert data, I have tried the above code only replacing

要插入数据,我已经尝试了上面的代码只替换

PreparedStatement statement= con.prepareStatement("SELECT * FROM jam 
 WHERE id='1'");

with

 PreparedStatement statement= con.prepareStatement("INSERT INTO jam(id,name) 
 VALUES ('','Charlie Sheen')");

But its showing some errors. Could you please tell me where is the problem in my code.

但它显示了一些错误。你能告诉我我的代码中的问题在哪里吗?

Thanks :)

谢谢 :)

回答by mstzn

If your primary key is auto increment,you can try this;

如果你的主键是自动递增的,你可以试试这个;

  PreparedStatement statement= con.prepareStatement("INSERT INTO jam(name) 
     VALUES (?)");

    statement.setString(1,"Charlie Sheen");

statement.execute();

回答by Anshu

If you have to insert lots of records, use batch insert

如果必须插入大量记录,请使用批量插入

    import java.sql.Connection;
    import java.sql.PreparedStatement;
    ?
    //...
    ?
    String sql = "INSERT INTO jam(id, name) VALUES (?, ?)";
    Connection con = DriverManager.getConnection("jdbc:mysql://localhost:3306/test","root","");  
 PreparedStatement ps = connection.prepareStatement(sql);
    ?
    for (Employee employee: employees) {
        ps.setString(1, employee.getId());
    ????ps.setString(2, employee.getName());
    ????ps.addBatch();
    }
    ps.executeBatch();
    ps.close();
    connection.close();??

回答by Gianmarco

I think you can also use this (if the ID is auto-increment)

我想你也可以使用这个(如果 ID 是自动递增的)

"INSERT INTO jam(name) VALUES ('Charlie Sheen')"

in any case, If you do not know the value of a specific int field I suggest not to write it into the query, it will be setted by default.

无论如何,如果您不知道特定 int 字段的值,我建议不要将其写入查询中,它将默认设置。

I think, if you set and INTEGER column = '', it could be a problem to the mysql.

我想,如果你设置了INTEGER column='',那可能是mysql的问题。

usually, I do not put numbers inside the ->''

通常,我不会将数字放在 ->''

回答by nagendra babu

@PostMapping("/save")
public void save(@RequestBody EmployeeListModel employeeListModels) throws SQLException{

    Connection connection=MyDataSource.getConnection(); 

     try{

    connection.setAutoCommit(false);
    PreparedStatement statement = connection.prepareStatement("insert into employee(Id,first_name,last_name,email) values (?,?,?,?)");
    List<EmployeeModel> employeeModels = employeeListModels.getModels();

    Iterator<EmployeeModel> iterator = employeeModels.iterator();

    while(iterator.hasNext()){
        EmployeeModel model = iterator.next();
        statement.setInt(1, model.getId());
        statement.setString(2, model.getFirstName());
        statement.setString(3, model.getLastName());
        statement.setString(4, model.getEmail());
        statement.addBatch();

    }

    int[] updates = statement.executeBatch();

    for(int i=0;i<updates.length;i++){
        if(updates[i] == -2){
            System.out.println("executed fail"+i);
        }
        else{
            System.out.println("executed:"+i+"successful"+updates[i]+"updated");
        }


    }

    connection.commit();
    statement.close();
    connection.close();
     }catch (Exception e) {
        e.printStackTrace();
    }