Java Apache POI 读取 Word (.doc) 文件并获取使用的命名样式
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Java Apache POI read Word (.doc) file and get named styles used
提问by Ashaelon
I am trying to read a Microsoft Word 2003 Document (.doc) using poi-scratchpad-3.8 (HWPF). I need to either read the file word by word, or character by character. Either way is fine for what I need. Once I have read either a character or word, I need to get the style name that is applied to the word/character. So, the question is, how do I get the style name used for a word or character when reading the .doc file?
我正在尝试使用 poi-scratchpad-3.8 (HWPF) 读取 Microsoft Word 2003 文档 (.doc)。我需要逐字或逐字读取文件。无论哪种方式都适合我的需要。一旦我阅读了一个字符或单词，我需要获取应用于该单词/字符的样式名称。所以，问题是，如何在阅读 .doc 文件时获取用于单词或字符的样式名称？
EDIT
编辑
I am adding the code that I used to attempt this. If anyone wants to attempt this, good luck.
我正在添加我用来尝试此操作的代码。如果有人想尝试这个，祝你好运。
private void processDoc(String path) throws Exception {
System.out.println(path);
POIFSFileSystem fis = new POIFSFileSystem(new FileInputStream(path));
HWPFDocument wdDoc = new HWPFDocument(fis);
// list all style names and indexes in stylesheet
for (int j = 0; j < wdDoc.getStyleSheet().numStyles(); j++) {
if (wdDoc.getStyleSheet().getStyleDescription(j) != null) {
System.out.println(j + ": " + wdDoc.getStyleSheet().getStyleDescription(j).getName());
} else {
// getStyleDescription returned null
System.out.println(j + ": " + null);
}
}
// set range for entire document
Range range = wdDoc.getRange();
// loop through all paragraphs in range
for (int i = 0; i < range.numParagraphs(); i++) {
Paragraph p = range.getParagraph(i);
// check if style index is greater than total number of styles
if (wdDoc.getStyleSheet().numStyles() > p.getStyleIndex()) {
System.out.println(wdDoc.getStyleSheet().numStyles() + " -> " + p.getStyleIndex());
StyleDescription style = wdDoc.getStyleSheet().getStyleDescription(p.getStyleIndex());
String styleName = style.getName();
// write style name and associated text
System.out.println(styleName + " -> " + p.text());
} else {
System.out.println("\n" + wdDoc.getStyleSheet().numStyles() + " ----> " + p.getStyleIndex());
}
}
回答by Gagravarr
I would suggest that you take a look at the sourcecode to WordExtractor from Apache Tika, as it's a great example of getting text and styling from a Word document using Apache POI
我建议您查看Apache Tika 中 WordExtractor的源代码，因为它是使用 Apache POI 从 Word 文档中获取文本和样式的一个很好的例子
Based on what you did and didn't say in your question, I suspect you're looking for something a little like this:
根据您在问题中所做的和没有说的，我怀疑您正在寻找类似这样的东西：
Range r = document.getRange();
for(int i=0; i<r.numParagraphs(); i++) {
Paragraph p = r.getParagraph(i);
String text = p.getText();
if( ! text.contains("What I'm Looking For")) {
// Try the next paragraph
continue;
}
if (document.getStyleSheet().numStyles()>p.getStyleIndex()) {
StyleDescription style =
document.getStyleSheet().getStyleDescription(p.getStyleIndex());
String styleName = style.getName();
System.out.println(styleName + " -> " + text);
}
else {
// Text has an unknown or invalid style
}
}
For anything more advanced, take a look at the WordExtractor sourcecode and see what else you can do with this sort of thing!
对于更高级的东西，请查看 WordExtractor 源代码，看看您还可以用这种东西做什么！
