bash 如何在不进入容器的情况下运行docker容器
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How can I run docker container without entering into container
提问by nick_gabpe
I have Dockefile
我有 Dockefile
FROM centos:7
So I have no entrypoint in dockerfile. Then I build it to image
所以我在 dockerfile 中没有入口点。然后我将它构建为图像
sudo docker build -t my_container .
Then I start it.
然后我开始。
sudo docker run -t my_container
And I get open tty to container
我打开 tty 到容器
root@my_container_id/
If I start it without -tit stopped immidiately after start.
How can I run docker container without start tty and without entrypoint?
如果我在没有它的情况下启动它，-t它会在启动后立即停止。如何在没有启动 tty 和入口点的情况下运行 docker 容器？
回答by naimdjon
You can start your container in a detachedmode:
您可以在分离模式下启动容器：
docker run -it -d my_container
The -doption here means your container will run in "detached" mode, in the background.
-d此处的选项意味着您的容器将在后台以“分离”模式运行。
If you want to attachthe container and drop to a shell, you can use:
如果要附加容器并放到外壳上，可以使用：
docker exec -it my_container /bin/bash
Note, if your container is based on an alpine image, you need to use sh, i.e.:
请注意，如果您的容器基于 alpine 映像，则需要使用sh，即：
docker exec -it my_container /bin/sh
回答by kstromeiraos
You can't do that. Your container lives if its main process is running, so you have to have a main process which is the process with PID 1 inside your container, and your container will be up if that process is running.
你不能那样做。如果主进程正在运行，您的容器就会存活，因此您必须有一个主进程，它是容器内 PID 为 1 的进程，如果该进程正在运行，您的容器就会启动。
