C# 枚举字母表的最快方法
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Quickest way to enumerate the alphabet
提问by Ben Aston
I want to iterate over the alphabet like so:
我想像这样迭代字母表：
foreach(char c in alphabet)
{
//do something with letter
}
Is an array of chars the best way to do this? (feels hacky)
字符数组是执行此操作的最佳方法吗？（感觉很坑爹）
Edit: The metric is "least typing to implement whilst still being readable and robust"
编辑：该指标是“最少要实现，同时仍具有可读性和健壮性”
采纳答案by Richard Szalay
(Assumes ASCII, etc)
（假设 ASCII 等）
for (char c = 'A'; c <= 'Z'; c++)
{
//do something with letter
}
Alternatively, you could split it out to a provider and use an iterator (if you're planning on supporting internationalisation):
或者，您可以将其拆分为提供者并使用迭代器（如果您计划支持国际化）：
public class EnglishAlphabetProvider : IAlphabetProvider
{
public IEnumerable<char> GetAlphabet()
{
for (char c = 'A'; c <= 'Z'; c++)
{
yield return c;
}
}
}
IAlphabetProvider provider = new EnglishAlphabetProvider();
foreach (char c in provider.GetAlphabet())
{
//do something with letter
}
回答by Bobby
You could do this:
你可以这样做：
for(int i = 65; i <= 95; i++)
{
//use System.Convert.ToChar() f.e. here
doSomethingWithTheChar(Convert.ToChar(i));
}
Though, not the best way either. Maybe we could help better if we would know the reason for this.
虽然，也不是最好的方法。如果我们知道这样做的原因，也许我们可以提供更好的帮助。
回答by Colin Newell
Or you could do,
或者你可以这样做
string alphabet = "abcdefghijklmnopqrstuvwxyz";
foreach(char c in alphabet)
{
//do something with letter
}
回答by Chris
回答by John Boker
Enumerable.Range(65, 26).Select(a => new { A = (char)(a) }).ToList().ForEach(c => Console.WriteLine(c.A));
回答by shankar.siva
var alphabet = Enumerable.Range(0, 26).Select(i => Convert.ToChar('A' + i));
