bash 如何在bash中将元素存储到数组
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How to store elements to an array in bash
提问by john doe
I got again tiny problem I would like to store strings in array I got following code:
我又遇到了一个小问题，我想将字符串存储在数组中，我得到了以下代码：
echo -e "Enter an amount"
read n
for ((i=0;i<n;i++));
do
echo "Enter number $i "
read ${array[$i]}
done
echo -e "$array[@]}"
Can you have a quick look a help me ? Thanks
你能帮我快速看看吗？谢谢
回答by ShankarG
Line 5 should probably read as:
第 5 行应该读作：
read array[$i]
${array[$i]}, which is what you have at present, will output the value of the element of the array with the subscript $i. The readcommand reads user input into a specified variable, so you need to specify the variable name.
${array[$i]}，这就是你目前所拥有的，将输出带有下标$i的数组元素的值。该read命令将用户输入读取到指定的变量中，因此您需要指定变量名称。
回答by glenn Hymanman
you could also write
你也可以写
array=()
for ?((i=0; i<n; i++)); do
read -p "Enter number $i "
array+=($REPLY)
done
