C语言 C - 将 time_t 转换为格式为 YYYY-MM-DD HH:MM:SS 的字符串
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C - Convert time_t to string with format YYYY-MM-DD HH:MM:SS
提问by dmessf
Is there any way to convert a time_tto a std::stringwith the format YYYY-MM-DD HH:MM:SSautomatically while keeping the code portable?
有没有什么办法的转换time_t到一个std::string格式为YYYY-MM-DD HH：MM：SS自动同时保持代码的可移植性？
回答by Jerry Coffin
Use localtimeto convert the time_tto a struct tm. You can use strftimeto print the desired data from that.
用于localtime将 转换time_t为struct tm。您可以使用它strftime来打印所需的数据。
char buff[20];
time_t now = time(NULL);
strftime(buff, 20, "%Y-%m-%d %H:%M:%S", localtime(&now));
回答by jer
Your only real option off the top of my head is either to write your own routine, or use the ctime() function defined in POSIX.1/C90. ctime() is certainly worth looking into, but if your date is not in the right timezone already, you will run into issues.
你唯一真正的选择是编写自己的例程，或者使用 POSIX.1/C90 中定义的 ctime() 函数。ctime() 当然值得研究，但如果您的日期不在正确的时区，您将遇到问题。
EDIT: I didn't think about using localtime as mentioned by Jerry below. Converting it to a struct tm does give you more possibilities including what he mentions, and strptime().
编辑：我没有考虑使用下面 Jerry 提到的 localtime。将其转换为 struct tm 确实为您提供了更多可能性，包括他提到的内容和 strptime()。
