bash 在bash中搜索数组返回索引
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Search array return index in bash
提问by matt
Just pesuocode but this is essentially what I would like to do.
只是 pesuocode 但这基本上是我想做的。
Array=("1" "Linux" "Test system"
"2" "Windows" "Workstation"
"3" "Windows" "Workstation")
echo "number " ${array[search ""]} "is a" ${array[search "" +1]} ${array[search "" +2])}
Is this possible with bash? I could only find info on search and replace. I didn't see anything That would return and index.
这可以用 bash 吗？我只能找到有关搜索和替换的信息。我没有看到任何会返回和索引的东西。
回答by user123444555621
Something like that should work:
这样的事情应该工作：
search() {
local i=1;
for str in "${array[@]}"; do
if [ "$str" = "" ]; then
echo $i
return
else
((i++))
fi
done
echo "-1"
}
While looping over the array to find the index is certainly possible, this alternative solution with an associative array is more practical:
虽然循环遍历数组以找到索引肯定是可能的，但这种带有关联数组的替代解决方案更实用：
array=([1,os]="Linux" [1,type]="Test System"
[2,os]="Windows" [2,type]="Work Station"
[3,os]="Windows" [3,type]="Work Station")
echo "number is a ${array[,os]} ${array[,type]}"
回答by Carl Norum
You could modify this example from this linkto return an index without much trouble:
您可以从此链接修改此示例以轻松返回索引：
# Check if a value exists in an array
# @param mixed Needle
# @param array Haystack
# @return Success (0) if value exists, Failure (1) otherwise
# Usage: in_array "$needle" "${haystack[@]}"
# See: http://fvue.nl/wiki/Bash:_Check_if_array_element_exists
in_array() {
local hay needle=
shift
for hay; do
[[ $hay == $needle ]] && return 0
done
return 1
}
