Linux 确定 CPU 利用率
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Determining CPU utilization
提问by
Is there a command or any other way to get the current or average CPU utilization(for a multi-processor environment) in Linux?
是否有命令或任何其他方式来获取Linux 中的当前或平均CPU 利用率（对于多处理器环境）？
I am using embedded Linux in a small system. Basically, I need to determine the CPU utilization, so that if it is high, I can instead divert a new process to another controller in the system, rather than executing on the main processor, which could be busy doing a more important process.
我在一个小型系统中使用嵌入式 Linux。基本上，我需要确定 CPU 利用率，以便如果它很高，我可以将新进程转移到系统中的另一个控制器，而不是在主处理器上执行，主处理器可能忙于执行更重要的进程。
This question is not about merely prioritizing processes, the other controller can sufficiently handle the new process, just that when the main processor is not busy, I would prefer it to do the execution.
这个问题不仅仅是优先处理进程，另一个控制器可以充分处理新进程，只是当主处理器不忙时，我更愿意它来执行。
采纳答案by caf
You need to sample the values in /proc/statat two times, and calculate the average utilisation over that time. (Instantaneous utilisation doesn't make a whole lot of sense - it'll always be 100% on a single core machine, since your utilsation-measuring code is running whenever it looks).
您需要对值/proc/stat进行两次采样，并计算这段时间内的平均利用率。（即时利用率并没有多大意义——它在单核机器上总是 100%，因为您的利用率测量代码无论何时都在运行）。
回答by doron
The /proc filesystem has all kinds of interesting information. Look at man procfor more information.
/proc 文件系统有各种有趣的信息。查看man proc更多信息。
回答by Andrew
Just use top if it is available. You can use it in a non-interactive mode:
如果可用，只需使用 top 。您可以在非交互模式下使用它：
top -n 1
If you want something specific then just grep that output. The exact details will depend on how your top command formats its output, but for example:
如果你想要一些特定的东西，那么只需 grep 那个输出。确切的细节将取决于您的 top 命令如何格式化其输出，但例如：
top -n 1 | grep 'Load'
回答by oguzalb
cat /proc/stat
you will see something like this
你会看到这样的东西
cpu 178877 11039 58012 5027374 22025 2616 1298 0 0
cpu0 122532 8808 34213 2438147 10881 1050 448 0 0
cpu1 56344 2230 23799 2589227 11143 1565 850 0 0
Simply take the sums of first three numbers and divide them with sums of first four integer
只需取前三个数字的总和并将它们除以前四个整数的总和
The first 4 numbers are user, nice, system, and idle times
前 4 个数字是用户、nice、系统和空闲时间
note: This gives overall average. If you want to take spontaneous average, you should take two samples and subtract them from each other before the divide.
注意：这给出了总体平均值。如果要取自发平均值，则应取两个样本并在除法之前将它们相减。
回答by oguzalb
The answer to the question after much searching and tinkering:
经过大量搜索和修补后问题的答案：
#include <stdio.h>
#include <stdlib.h>
int main(void)
{
long double a[4], b[4], loadavg;
FILE *fp;
char dump[50];
for(;;)
{
fp = fopen("/proc/stat","r");
fscanf(fp,"%*s %Lf %Lf %Lf %Lf",&a[0],&a[1],&a[2],&a[3]);
fclose(fp);
sleep(1);
fp = fopen("/proc/stat","r");
fscanf(fp,"%*s %Lf %Lf %Lf %Lf",&b[0],&b[1],&b[2],&b[3]);
fclose(fp);
loadavg = ((b[0]+b[1]+b[2]) - (a[0]+a[1]+a[2])) / ((b[0]+b[1]+b[2]+b[3]) - (a[0]+a[1]+a[2]+a[3]));
printf("The current CPU utilization is : %Lf\n",loadavg);
}
return(0);
}
I am getting the same values as those reported by the System Monitor.
我得到的值与系统监视器报告的值相同。
