php 调用未定义的函数 imagecreatefromjpeg() 并启用 GD
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Call to undefined function imagecreatefromjpeg() and GD enabled
提问by FoXaWy
im working on ubuntu 14.04 LTS with PHP 5.5.9 with GD enabled and i doubled check with but still showing me this msg everytime i try to use imagecreatefromjpeg()
我正在 ubuntu 14.04 LTS 上使用 PHP 5.5.9 启用 GD，我仔细检查了但仍然在每次我尝试使用 imagecreatefromjpeg() 时向我展示这个 msg
Fatal error: Call to undefined function imagecreatefromjpeg() in /../library/image.php on line 34
致命错误：在第 34 行调用 /../library/image.php 中未定义的函数 imagecreatefromjpeg()
i even tried to check on it from command line by using this
我什至尝试使用它从命令行检查它
php -r "var_dump(function_exists('imageantialias'));"
and it gives me back bool(false)
它让我回到 bool(false)
is there anyway to fix this without re compiling it?
有没有办法在不重新编译的情况下解决这个问题？
回答by hiwjd0
I think you've installed an incomplete version of gd.
When you compile the gdextension, use the flag --with-jpeg-dir=DIRand --with-freetype-dir=DIR
我认为您安装了不完整版本的gd.
编译gd扩展时，使用标志--with-jpeg-dir=DIR和--with-freetype-dir=DIR
ps. dont forget make clean
附：不要忘记make clean
picture below is the incompleteversion of gd:
下图是incompletegd的版本：
picture below is the completeversion of gd:
下图是completegd的版本：
回答by Meloman
In my case, GD was missing after upgrading to PHP 7.3. So, I just added it by using the following command :
就我而言，升级到 PHP 7.3 后 GD 不见了。所以，我只是使用以下命令添加了它：
sudo apt-get install php7.3-gd
回答by tarun
Try this
<?php
function LoadJpeg($imgname)
{
/* Attempt to open */
$im = @imagecreatefromjpeg($imgname);
/* See if it failed */
if(!$im)
{
/* Create a black image */
$im = imagecreatetruecolor(150, 30);
$bgc = imagecolorallocate($im, 255, 255, 255);
$tc = imagecolorallocate($im, 0, 0, 0);
imagefilledrectangle($im, 0, 0, 150, 30, $bgc);
/* Output an error message */
imagestring($im, 1, 5, 5, 'Error loading ' . $imgname, $tc);
}
return $im;
}
header('Content-Type: image/jpeg');
$img = LoadJpeg('bogus.image');
imagejpeg($img);
imagedestroy($img);
?>
