Python 冒号预期错误
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Colon expected error
提问by Leem.fin
I have a simple problem.
我有一个简单的问题。
class MyObj:
...
def get_file_name(self):
return "myfile.txt"
some_obj = MyObj()
# Error: Colon expected
with open some_obj.get_file_name() as f:
print("dealing with file ...")
# do something on f
MyObjclass has a method called get_file_name(self), which returns a string of file name.
MyObj类有一个名为 的方法get_file_name(self)，它返回一串文件名。
In the code of opening the file, I got compiler error Colon expected. I don't see where/why colon needed. Please help me why I got this error?
在打开文件的代码中，我得到了编译器错误Colon expected。我不明白哪里/为什么需要冒号。请帮助我为什么会出现此错误？
采纳答案by rodrigo
This line:
这一行：
with open some_obj.get_file_name() as f:
should be:
应该：
with open(some_obj.get_file_name()) as f:
That is, open()is a function!
也就是说，open()是一个函数！
回答by mvelay
bad syntax in your code, try adding brackets when opening your file:
代码中的语法错误，请在打开文件时尝试添加括号：
# Error: Colon expected
with open(some_obj.get_file_name()) as f:
print("dealing with file ...")
# do something on f
