Java 将 RGB 值转换为颜色名称

Convert RGB values to color name

提问by user236501

How can I convert a color in RGB format into a color name?

如何将 RGB 格式的颜色转换为颜色名称？

Examples:

例子：

• (0, 0, 255) -> "blue"
• (255, 0, 0) -> "red"
• (128, 128, 128) -> "grey"

• (0, 0, 255) -> "蓝色"
• (255, 0, 0) -> "红色"
• (128, 128, 128) -> “灰色”

采纳答案by Ivan

1. Populate a list of "known" colors.

2. For each known color compute:

   rgbDistance = Math.abs(myColor.getRed() - colorI.getRed() + 
                 Math.abs(myColor.getGreen() - colorI.getGreen()) +
                 Math.abs(myColor.getBlue() - colorI.getBlue())  
   

3. Return the name of colorIfor which rgbDistancewas smallest.

1. 填充“已知”颜色列表。

2. 对于每个已知的颜色计算：

   rgbDistance = Math.abs(myColor.getRed() - colorI.getRed() + 
                 Math.abs(myColor.getGreen() - colorI.getGreen()) +
                 Math.abs(myColor.getBlue() - colorI.getBlue())  
   

3. 返回的名字colorI为这rgbDistance是最小的。

回答by Evan Mulawski

Not all RGB values have aliases. You may need to create an array containing arrays of Red, Green, Blue, and Alias values. Then you would iterate over that array comparing the RGB values.

并非所有 RGB 值都有别名。您可能需要创建一个包含 Red、Green、Blue 和 Alias 值数组的数组。然后您将遍历该数组以比较 RGB 值。

http://en.wikipedia.org/wiki/List_of_colors

http://en.wikipedia.org/wiki/List_of_colors

Edit:

编辑：

Sample:

样本：

//array of known aliases and rgb values
ArrayList colorList = new ArrayList();
colorList.add(new String[] {"255", "0", "0", "Red"});
//etc...

Color c = new Color(255, 0, 0); //test color
String name = "Unknown";
for (String[] color : colorList)
{
    int r = Integer.parseInt(color[0]) //red value
    int g = Integer.parseInt(color[1]) //green value
    int b = Integer.parseInt(color[2]) //blue value
    String alias = color[3];

    if ((c.getRed() == r) && (c.getGreen() == g) && (c.getBlue() == b))
    {
        name = alias; //found it
        break;
    }
}

回答by sfussenegger

You could simply build a lookup table, e.g. using the constants from Color class itself:

您可以简单地构建一个查找表，例如使用 Color 类本身的常量：

Map<Integer, String> map = new HashMap<Integer, String>();
for (Field f : Color.class.getFields()) {
  if (f.getType() == Color.class) {
    Color c = (Color) f.get(null);
    map.put(c.getRGB(), f.getName()); 
  }
}

If you want all HTML colors or all those form Wikipedia linked by @evan, you have still a little homework to do though.

如果您想要所有 HTML 颜色或所有由 @evan 链接的维基百科形式，您仍然需要做一些功课。

EDIT resulting map:

编辑结果地图：

0xff00ffff: CYAN
0xff0000ff: BLUE
0xffc0c0c0: LIGHT_GRAY
0xff808080: GRAY
0xffffff00: YELLOW
0xffff0000: RED
0xffffafaf: PINK
0xff000000: BLACK
0xff00ff00: GREEN
0xffffc800: ORANGE
0xff404040: DARK_GRAY
0xffff00ff: MAGENTA
0xffffffff: WHITE

回答by Chris Pfohl

Hmm, that's a kind of fun problem. I can think of a few solutions:

嗯，这是一个有趣的问题。我可以想到几个解决方案：

1. You could do a bit of guesswork depending on the relationships between the R-G-B values (for example, if one color is very dominant you guess that one, but if there's a bit of other color you get more and more likely to guess the combination of those two emitted colors, if all three are close to equal then guess white, grey, or black depending on how high the average of the three values is, if two are high and the other is low guess the combinatoin of the two, etc. etc.)

2. You could go for a more learning approach where you set some initial guesses (as above) and then improve on those based on feedback from users.

1. 您可以根据 RGB 值之间的关系进行一些猜测（例如，如果一种颜色占主导地位，您会猜测该颜色，但如果有一些其他颜色，您就会越来越有可能猜测这些颜色的组合两种发出的颜色，如果所有三个都接近相等，则根据三个值的平均值的高低猜测白色、灰色或黑色，如果两个高而另一个低，则猜测两者的组合，等等。 .)

2. 您可以采用更多学习方法，在其中设置一些初始猜测（如上所述），然后根据用户的反馈改进这些猜测。

Unfortunately this problem is relatively subjective (although the question is not!) as people's perception of color varies widely between culture and even gender (see Randall Munroe's "study" on it).

不幸的是，这个问题是相对主观的（尽管问题不是！）因为人们对颜色的看法因文化甚至性别而异（参见兰德尔·门罗对此的“研究”）。

If you want a specific subset of RGB values (like the ones that are given constants in Java or C# you can iterate through each and compare, finally returning some default value if it's not equal to any of them).

如果你想要一个特定的 RGB 值子集（比如在 Java 或 C# 中给定常量的那些，你可以遍历每个并比较，如果它不等于它们中的任何一个，最后返回一些默认值）。

[EDIT]

[编辑]

Ahh! Colorblind users eh? Have you considered creating a setting which lets the user specify which colors they have trouble differentiating? If you did that you could let them know that something is "20% Redder than Green" (if, for instance, they had red-green colorblindness, which is most common). That would be pretty simple. They select a pixel, and you follow this pseudocode:

啊！色盲用户是吧？您是否考虑过创建一个设置，让用户指定他们难以区分的颜色？如果你这样做，你可以让他们知道某些东西“比绿色红 20%”（例如，如果他们有红绿色盲，这是最常见的）。那会很简单。他们选择一个像素，然后按照以下伪代码进行操作：

if( userColorTrouble == RedGreen )
{
    int redVal = colorInQuestion.GetRed();
    int greenVal = colorInQuestion.GetGreen();
    if( redVal > greenVal )
    {
         return "The color is " + (double)redVal / (redVal + greenVal) - .5d + "% redder than green";
    }
    else
    {
         return "The color is " + (double)greenVal / (redVal + greenVal) - .5d + "% greener than red";
    }
}

That could be a simpler, and more useful solution.

这可能是一个更简单、更有用的解决方案。

回答by baklarz2048

Frist of all convert pixels from RGB to HSV. It's much easier to define color ranges in HSV than in RGB.

首先将像素从 RGB 转换为 HSV。在 HSV 中定义颜色范围比在 RGB 中容易得多。

/**
*
*@author Tomasz Drobiszewski
*/
public class Color {
    /**
     * Human color table.
     */
    public static final int [] [] colors  = {
            {-1,-10,-360,-0,-100,-10,-80},
            {1,0,360,0,100,0,50},
            {2,0,360,0,15,50,130},
            {3,0,360,0,15,130,210},
            {4,-15,15,15,100,50,255},
            {5,15,45,15,100,50,255},
            {6,45,75,15,100,50,255},
            {7,75,105,15,100,50,255},
            {8,105,135,15,100,50,255},
            {9,135,165,15,100,50,255},
            {10,165,195,15,100,50,255},
            {11,195,225,15,100,50,255},
            {12,225,255,15,100,50,255},
            {13,255,285,15,100,50,255},
            {14,285,315,15,100,50,255},
            {15,315,345,15,100,50,255},
            {16,345,375,15,100,50,255},
            {17,0,360,0,15,210,255} 
    };

    /**
     * Color names.
     */
    public static final String [] humanColors = {
            "unrecognized", 
            "black", //black colors[1]
            "grey",
            "light_grey",
            "red",
            "orange",
            "yellow",
            "jasny_zielony",
            "zielony",
            "zielony",
            "turkusowy",
            "jasny_niebieski",
            "niebieski",
            "fioletowy",
            "fioletowy",
            "rozowy",
            "czerwony",
            "bialy",
        };

    /**
     * Convert from  RGB do HSV
     * 
     * @param r
     * @param g
     * @param b
     * @param hsv
     */
    public static void rgb2hsv(int r, int g, int b, int hsv[]) {

        int min; // Min. value of RGB
        int max; // Max. value of RGB
        int delMax; // Delta RGB value

        if (r > g) {
            min = g;
            max = r;
        } else {
            min = r;
            max = g;
        }
        if (b > max)
            max = b;
        if (b < min)
            min = b;

        delMax = max - min;

        float H = 0, S;
        float V = max;

        if (delMax == 0) {
            H = 0;
            S = 0;

        } else {
            S = delMax / (float) max;
            if (r == max)
                H = ((g - b) / (float) delMax) * 60;
            else if (g == max)
                H = (2 + (b - r) / (float) delMax) * 60;
            else if (b == max)
                H = (4 + (r - g) / (float) delMax) * 60;

        }

        hsv[0] = (int) (H);
        hsv[1] = (int) (S * 100);
        hsv[2] = (int) V;
    }

    /**
     * Return human color index {@link Color#colors}
     * 
     * @param r
     * @param g
     * @param b
     * @return
     */
    public static int [] getHumanColor(int r, int g, int b) {
        int [] res = {0, 0, 0, 0};
        int[] hsv = new int[3];
        rgb2hsv(r, g, b, hsv);
        for (int i = 1; i < colors.length; i++) {
            if (hsv[0] <= colors[i][2] && hsv[0] >= colors[i][1]
                    && hsv[1] <= colors[i][4] && hsv[1] >= colors[i][3]
                    && hsv[2] <= colors[i][6] && hsv[2] >= colors[i][5]) {
                res[3] = i;
                res[0] = hsv[0];
                res[1] = hsv[1];
                res[2] = hsv[2];
                return res;
            }

        }
        return res;
    }

}

回答by cindyxiaoxiaoli

Here is a working sample codethat does that. It converts an rgb/hex value/awt color into the closest color name.

这是一个工作示例代码，可以做到这一点。它将 rgb/十六进制值/awt 颜色转换为最接近的颜色名称。

import java.awt.Color;
import java.util.ArrayList;

/**
 * Java Code to get a color name from rgb/hex value/awt color
 * 
 * The part of looking up a color name from the rgb values is edited from
 * https://gist.github.com/nightlark/6482130#file-gistfile1-java (that has some errors) by Ryan Mast (nightlark)
 * 
 * @author Xiaoxiao Li
 * 
 */
public class ColorUtils {

    /**
     * Initialize the color list that we have.
     */
    private ArrayList<ColorName> initColorList() {
        ArrayList<ColorName> colorList = new ArrayList<ColorName>();
        colorList.add(new ColorName("AliceBlue", 0xF0, 0xF8, 0xFF));
        colorList.add(new ColorName("AntiqueWhite", 0xFA, 0xEB, 0xD7));
        colorList.add(new ColorName("Aqua", 0x00, 0xFF, 0xFF));
        colorList.add(new ColorName("Aquamarine", 0x7F, 0xFF, 0xD4));
        colorList.add(new ColorName("Azure", 0xF0, 0xFF, 0xFF));
        colorList.add(new ColorName("Beige", 0xF5, 0xF5, 0xDC));
        colorList.add(new ColorName("Bisque", 0xFF, 0xE4, 0xC4));
        colorList.add(new ColorName("Black", 0x00, 0x00, 0x00));
        colorList.add(new ColorName("BlanchedAlmond", 0xFF, 0xEB, 0xCD));
        colorList.add(new ColorName("Blue", 0x00, 0x00, 0xFF));
        colorList.add(new ColorName("BlueViolet", 0x8A, 0x2B, 0xE2));
        colorList.add(new ColorName("Brown", 0xA5, 0x2A, 0x2A));
        colorList.add(new ColorName("BurlyWood", 0xDE, 0xB8, 0x87));
        colorList.add(new ColorName("CadetBlue", 0x5F, 0x9E, 0xA0));
        colorList.add(new ColorName("Chartreuse", 0x7F, 0xFF, 0x00));
        colorList.add(new ColorName("Chocolate", 0xD2, 0x69, 0x1E));
        colorList.add(new ColorName("Coral", 0xFF, 0x7F, 0x50));
        colorList.add(new ColorName("CornflowerBlue", 0x64, 0x95, 0xED));
        colorList.add(new ColorName("Cornsilk", 0xFF, 0xF8, 0xDC));
        colorList.add(new ColorName("Crimson", 0xDC, 0x14, 0x3C));
        colorList.add(new ColorName("Cyan", 0x00, 0xFF, 0xFF));
        colorList.add(new ColorName("DarkBlue", 0x00, 0x00, 0x8B));
        colorList.add(new ColorName("DarkCyan", 0x00, 0x8B, 0x8B));
        colorList.add(new ColorName("DarkGoldenRod", 0xB8, 0x86, 0x0B));
        colorList.add(new ColorName("DarkGray", 0xA9, 0xA9, 0xA9));
        colorList.add(new ColorName("DarkGreen", 0x00, 0x64, 0x00));
        colorList.add(new ColorName("DarkKhaki", 0xBD, 0xB7, 0x6B));
        colorList.add(new ColorName("DarkMagenta", 0x8B, 0x00, 0x8B));
        colorList.add(new ColorName("DarkOliveGreen", 0x55, 0x6B, 0x2F));
        colorList.add(new ColorName("DarkOrange", 0xFF, 0x8C, 0x00));
        colorList.add(new ColorName("DarkOrchid", 0x99, 0x32, 0xCC));
        colorList.add(new ColorName("DarkRed", 0x8B, 0x00, 0x00));
        colorList.add(new ColorName("DarkSalmon", 0xE9, 0x96, 0x7A));
        colorList.add(new ColorName("DarkSeaGreen", 0x8F, 0xBC, 0x8F));
        colorList.add(new ColorName("DarkSlateBlue", 0x48, 0x3D, 0x8B));
        colorList.add(new ColorName("DarkSlateGray", 0x2F, 0x4F, 0x4F));
        colorList.add(new ColorName("DarkTurquoise", 0x00, 0xCE, 0xD1));
        colorList.add(new ColorName("DarkViolet", 0x94, 0x00, 0xD3));
        colorList.add(new ColorName("DeepPink", 0xFF, 0x14, 0x93));
        colorList.add(new ColorName("DeepSkyBlue", 0x00, 0xBF, 0xFF));
        colorList.add(new ColorName("DimGray", 0x69, 0x69, 0x69));
        colorList.add(new ColorName("DodgerBlue", 0x1E, 0x90, 0xFF));
        colorList.add(new ColorName("FireBrick", 0xB2, 0x22, 0x22));
        colorList.add(new ColorName("FloralWhite", 0xFF, 0xFA, 0xF0));
        colorList.add(new ColorName("ForestGreen", 0x22, 0x8B, 0x22));
        colorList.add(new ColorName("Fuchsia", 0xFF, 0x00, 0xFF));
        colorList.add(new ColorName("Gainsboro", 0xDC, 0xDC, 0xDC));
        colorList.add(new ColorName("GhostWhite", 0xF8, 0xF8, 0xFF));
        colorList.add(new ColorName("Gold", 0xFF, 0xD7, 0x00));
        colorList.add(new ColorName("GoldenRod", 0xDA, 0xA5, 0x20));
        colorList.add(new ColorName("Gray", 0x80, 0x80, 0x80));
        colorList.add(new ColorName("Green", 0x00, 0x80, 0x00));
        colorList.add(new ColorName("GreenYellow", 0xAD, 0xFF, 0x2F));
        colorList.add(new ColorName("HoneyDew", 0xF0, 0xFF, 0xF0));
        colorList.add(new ColorName("HotPink", 0xFF, 0x69, 0xB4));
        colorList.add(new ColorName("IndianRed", 0xCD, 0x5C, 0x5C));
        colorList.add(new ColorName("Indigo", 0x4B, 0x00, 0x82));
        colorList.add(new ColorName("Ivory", 0xFF, 0xFF, 0xF0));
        colorList.add(new ColorName("Khaki", 0xF0, 0xE6, 0x8C));
        colorList.add(new ColorName("Lavender", 0xE6, 0xE6, 0xFA));
        colorList.add(new ColorName("LavenderBlush", 0xFF, 0xF0, 0xF5));
        colorList.add(new ColorName("LawnGreen", 0x7C, 0xFC, 0x00));
        colorList.add(new ColorName("LemonChiffon", 0xFF, 0xFA, 0xCD));
        colorList.add(new ColorName("LightBlue", 0xAD, 0xD8, 0xE6));
        colorList.add(new ColorName("LightCoral", 0xF0, 0x80, 0x80));
        colorList.add(new ColorName("LightCyan", 0xE0, 0xFF, 0xFF));
        colorList.add(new ColorName("LightGoldenRodYellow", 0xFA, 0xFA, 0xD2));
        colorList.add(new ColorName("LightGray", 0xD3, 0xD3, 0xD3));
        colorList.add(new ColorName("LightGreen", 0x90, 0xEE, 0x90));
        colorList.add(new ColorName("LightPink", 0xFF, 0xB6, 0xC1));
        colorList.add(new ColorName("LightSalmon", 0xFF, 0xA0, 0x7A));
        colorList.add(new ColorName("LightSeaGreen", 0x20, 0xB2, 0xAA));
        colorList.add(new ColorName("LightSkyBlue", 0x87, 0xCE, 0xFA));
        colorList.add(new ColorName("LightSlateGray", 0x77, 0x88, 0x99));
        colorList.add(new ColorName("LightSteelBlue", 0xB0, 0xC4, 0xDE));
        colorList.add(new ColorName("LightYellow", 0xFF, 0xFF, 0xE0));
        colorList.add(new ColorName("Lime", 0x00, 0xFF, 0x00));
        colorList.add(new ColorName("LimeGreen", 0x32, 0xCD, 0x32));
        colorList.add(new ColorName("Linen", 0xFA, 0xF0, 0xE6));
        colorList.add(new ColorName("Magenta", 0xFF, 0x00, 0xFF));
        colorList.add(new ColorName("Maroon", 0x80, 0x00, 0x00));
        colorList.add(new ColorName("MediumAquaMarine", 0x66, 0xCD, 0xAA));
        colorList.add(new ColorName("MediumBlue", 0x00, 0x00, 0xCD));
        colorList.add(new ColorName("MediumOrchid", 0xBA, 0x55, 0xD3));
        colorList.add(new ColorName("MediumPurple", 0x93, 0x70, 0xDB));
        colorList.add(new ColorName("MediumSeaGreen", 0x3C, 0xB3, 0x71));
        colorList.add(new ColorName("MediumSlateBlue", 0x7B, 0x68, 0xEE));
        colorList.add(new ColorName("MediumSpringGreen", 0x00, 0xFA, 0x9A));
        colorList.add(new ColorName("MediumTurquoise", 0x48, 0xD1, 0xCC));
        colorList.add(new ColorName("MediumVioletRed", 0xC7, 0x15, 0x85));
        colorList.add(new ColorName("MidnightBlue", 0x19, 0x19, 0x70));
        colorList.add(new ColorName("MintCream", 0xF5, 0xFF, 0xFA));
        colorList.add(new ColorName("MistyRose", 0xFF, 0xE4, 0xE1));
        colorList.add(new ColorName("Moccasin", 0xFF, 0xE4, 0xB5));
        colorList.add(new ColorName("NavajoWhite", 0xFF, 0xDE, 0xAD));
        colorList.add(new ColorName("Navy", 0x00, 0x00, 0x80));
        colorList.add(new ColorName("OldLace", 0xFD, 0xF5, 0xE6));
        colorList.add(new ColorName("Olive", 0x80, 0x80, 0x00));
        colorList.add(new ColorName("OliveDrab", 0x6B, 0x8E, 0x23));
        colorList.add(new ColorName("Orange", 0xFF, 0xA5, 0x00));
        colorList.add(new ColorName("OrangeRed", 0xFF, 0x45, 0x00));
        colorList.add(new ColorName("Orchid", 0xDA, 0x70, 0xD6));
        colorList.add(new ColorName("PaleGoldenRod", 0xEE, 0xE8, 0xAA));
        colorList.add(new ColorName("PaleGreen", 0x98, 0xFB, 0x98));
        colorList.add(new ColorName("PaleTurquoise", 0xAF, 0xEE, 0xEE));
        colorList.add(new ColorName("PaleVioletRed", 0xDB, 0x70, 0x93));
        colorList.add(new ColorName("PapayaWhip", 0xFF, 0xEF, 0xD5));
        colorList.add(new ColorName("PeachPuff", 0xFF, 0xDA, 0xB9));
        colorList.add(new ColorName("Peru", 0xCD, 0x85, 0x3F));
        colorList.add(new ColorName("Pink", 0xFF, 0xC0, 0xCB));
        colorList.add(new ColorName("Plum", 0xDD, 0xA0, 0xDD));
        colorList.add(new ColorName("PowderBlue", 0xB0, 0xE0, 0xE6));
        colorList.add(new ColorName("Purple", 0x80, 0x00, 0x80));
        colorList.add(new ColorName("Red", 0xFF, 0x00, 0x00));
        colorList.add(new ColorName("RosyBrown", 0xBC, 0x8F, 0x8F));
        colorList.add(new ColorName("RoyalBlue", 0x41, 0x69, 0xE1));
        colorList.add(new ColorName("SaddleBrown", 0x8B, 0x45, 0x13));
        colorList.add(new ColorName("Salmon", 0xFA, 0x80, 0x72));
        colorList.add(new ColorName("SandyBrown", 0xF4, 0xA4, 0x60));
        colorList.add(new ColorName("SeaGreen", 0x2E, 0x8B, 0x57));
        colorList.add(new ColorName("SeaShell", 0xFF, 0xF5, 0xEE));
        colorList.add(new ColorName("Sienna", 0xA0, 0x52, 0x2D));
        colorList.add(new ColorName("Silver", 0xC0, 0xC0, 0xC0));
        colorList.add(new ColorName("SkyBlue", 0x87, 0xCE, 0xEB));
        colorList.add(new ColorName("SlateBlue", 0x6A, 0x5A, 0xCD));
        colorList.add(new ColorName("SlateGray", 0x70, 0x80, 0x90));
        colorList.add(new ColorName("Snow", 0xFF, 0xFA, 0xFA));
        colorList.add(new ColorName("SpringGreen", 0x00, 0xFF, 0x7F));
        colorList.add(new ColorName("SteelBlue", 0x46, 0x82, 0xB4));
        colorList.add(new ColorName("Tan", 0xD2, 0xB4, 0x8C));
        colorList.add(new ColorName("Teal", 0x00, 0x80, 0x80));
        colorList.add(new ColorName("Thistle", 0xD8, 0xBF, 0xD8));
        colorList.add(new ColorName("Tomato", 0xFF, 0x63, 0x47));
        colorList.add(new ColorName("Turquoise", 0x40, 0xE0, 0xD0));
        colorList.add(new ColorName("Violet", 0xEE, 0x82, 0xEE));
        colorList.add(new ColorName("Wheat", 0xF5, 0xDE, 0xB3));
        colorList.add(new ColorName("White", 0xFF, 0xFF, 0xFF));
        colorList.add(new ColorName("WhiteSmoke", 0xF5, 0xF5, 0xF5));
        colorList.add(new ColorName("Yellow", 0xFF, 0xFF, 0x00));
        colorList.add(new ColorName("YellowGreen", 0x9A, 0xCD, 0x32));
        return colorList;
    }

    /**
     * Get the closest color name from our list
     * 
     * @param r
     * @param g
     * @param b
     * @return
     */
    public String getColorNameFromRgb(int r, int g, int b) {
        ArrayList<ColorName> colorList = initColorList();
        ColorName closestMatch = null;
        int minMSE = Integer.MAX_VALUE;
        int mse;
        for (ColorName c : colorList) {
            mse = c.computeMSE(r, g, b);
            if (mse < minMSE) {
                minMSE = mse;
                closestMatch = c;
            }
        }

        if (closestMatch != null) {
            return closestMatch.getName();
        } else {
            return "No matched color name.";
        }
    }

    /**
     * Convert hexColor to rgb, then call getColorNameFromRgb(r, g, b)
     * 
     * @param hexColor
     * @return
     */
    public String getColorNameFromHex(int hexColor) {
        int r = (hexColor & 0xFF0000) >> 16;
        int g = (hexColor & 0xFF00) >> 8;
        int b = (hexColor & 0xFF);
        return getColorNameFromRgb(r, g, b);
    }

    public int colorToHex(Color c) {
        return Integer.decode("0x"
                + Integer.toHexString(c.getRGB()).substring(2));
    }

    public String getColorNameFromColor(Color color) {
        return getColorNameFromRgb(color.getRed(), color.getGreen(),
                color.getBlue());
    }

    /**
     * SubClass of ColorUtils. In order to lookup color name
     * 
     * @author Xiaoxiao Li
     * 
     */
    public class ColorName {
        public int r, g, b;
        public String name;

        public ColorName(String name, int r, int g, int b) {
            this.r = r;
            this.g = g;
            this.b = b;
            this.name = name;
        }

        public int computeMSE(int pixR, int pixG, int pixB) {
            return (int) (((pixR - r) * (pixR - r) + (pixG - g) * (pixG - g) + (pixB - b)
                    * (pixB - b)) / 3);
        }

        public int getR() {
            return r;
        }

        public int getG() {
            return g;
        }

        public int getB() {
            return b;
        }

        public String getName() {
            return name;
        }
    }
}

回答by rosterloh

In my case I was looking for a quick way to get the name of primary colours displayable on all on or all off LEDs so the following function works for me. Hope it's helpful to someone.

就我而言，我正在寻找一种快速方法来获取可在所有打开或所有关闭 LED 上显示的原色名称，因此以下功能对我有用。希望它对某人有帮助。

public static String getColourName(int c) {
    String name = "UNKNOWN";
    int colour = Color.BLACK;

    if(Color.red(c) > 127)  { colour |= Color.RED; }
    if(Color.green(c) > 127) { colour |= Color.GREEN; }
    if(Color.blue(c) > 127) { colour |= Color.BLUE; }

    switch (colour) {
        case Color.BLACK:
            name = "BLACK";
            break;
        case Color.BLUE:
            name = "BLUE";
            break;
        case Color.GREEN:
            name = "GREEN";
            break;
        case Color.CYAN:
            name = "CYAN";
            break;
        case Color.RED:
            name = "RED";
            break;
        case Color.MAGENTA:
            name = "MAGENTA";
            break;
        case Color.YELLOW:
            name = "YELLOW";
            break;
        case Color.WHITE:
            name = "WHITE";
            break;
    }
    return name;
}