Python TypeError: 'NoneType' 对象不可调用，BeautifulSoup
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TypeError: 'NoneType' object is not callable, BeautifulSoup
提问by Alpinestar22
I'm running into a strange error. I'm trying to do some basic parsing. Essentially, I'm gathering data in 'x' format, and want to return everything in a format that I can use. My immediate issue is that my code is returning a strange error. I have looked through some of the other posts / answers on here for the same issue, but out of context... it is truly hard to pinpoint the issue.
我遇到了一个奇怪的错误。我正在尝试做一些基本的解析。本质上，我正在以“x”格式收集数据，并希望以我可以使用的格式返回所有内容。我的直接问题是我的代码返回一个奇怪的错误。我已经浏览了此处针对同一问题的其他一些帖子/答案，但脱离了上下文……确实很难确定问题所在。
data = url.text
soup = BeautifulSoup(data, "html5lib")
results = [] # this is what my result set will end up as
def parseDiv(text):
#function takes one input parameter - a single div for which it will parse for specific items, and return it all as a dictionary
soup2 = BeautifulSoup(text)
title = soup2.find("a", "yschttl spt")
print title.text
print
return title.text
for result in soup.find_all("div", "res"):
"""
This is where the data is first handled - this would return a div with links, text, etc -
So, I pass the blurb of text into the parseDiv() function
"""
item = parseDiv(result)
results.append(item)
Obviously at this point, I've included my needed libraries... When I pull the code for soup2 (the second instantiation of bs4 on my new blurbs of text to be processed), and just print the input of my function, it all works.
显然在这一点上，我已经包含了我需要的库......当我拉出soup2的代码（bs4在我要处理的新文本上的第二次实例化），并且只打印我的函数的输入时，这一切作品。
Here is the error:
这是错误：
Traceback (most recent call last):
File "testdata.py", line 29, in <module>
item = parseDiv(result)
File "testdata.py", line 17, in parseDiv
soup2 = BeautifulSoup(text)
File "C:\Python27\lib\site-packages\bs4\__i
markup = markup.read()
TypeError: 'NoneType' object is not callable
采纳答案by Jayanth Koushik
You don't need to parse the divs once again. Try this:
您不需要再次解析 div。尝试这个：
for div in soup.find_all('div', 'res'):
a = div.find('a', 'yschttl spt')
if a:
print a.text
print
results.append(a)
