Python AttributeError: 'NoneType' 对象没有属性 'split'
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时间：2020-08-18 23:47:00 来源:igfitidea点击:
AttributeError: 'NoneType' object has no attribute 'split'
提问by MLSC
I have a script with these two functions:
我有一个具有这两个功能的脚本：
# Getting content of each page
def GetContent(url):
response = requests.get(url)
return response.content
# Extracting the sites
def CiteParser(content):
soup = BeautifulSoup(content)
print "---> site #: ",len(soup('cite'))
result = []
for cite in soup.find_all('cite'):
result.append(cite.string.split('/')[0])
return result
When I run program I have the following error:
当我运行程序时，出现以下错误：
result.append(cite.string.split('/')[0])
AttributeError: 'NoneType' object has no attribute 'split'
Output Sample:
输出样本：
URL: <URL That I use to search 'can be google, bing, etc'>
---> site #: 10
site1.com
.
.
.
site10.com
URL: <URL That I use to search 'can be google, bing, etc'>
File "python.py", line 49, in CiteParser
result.append(cite.string.split('/')[0])
AttributeError: 'NoneType' object has no attribute 'split'
采纳答案by user1767754
It can happen, that the string has nothing inside, than it is "None" type, so what I can suppose is to check first if your string is not "None"
可能会发生，字符串内部没有任何内容，而不是“无”类型，所以我可以假设首先检查您的字符串是否不是“无”
# Extracting the sites
def CiteParser(content):
soup = BeautifulSoup(content)
#print soup
print "---> site #: ",len(soup('cite'))
result = []
for cite in soup.find_all('cite'):
if cite.string is not None:
result.append(cite.string.split('/'))
print cite
return result
回答by cppcoder
for cite in soup.find_all('cite'):
if( (cite.string is None) or (len(cite.string) == 0)):
continue
result.append(cite.string.split('/')[0])
