php REQUEST_URI
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php REQUEST_URI
提问by user1118904
I have the following php script to read the request in URL :
我有以下 php 脚本来读取 URL 中的请求：
$id = '/' != ($_SERVER['REQUEST_URI']) ?
str_replace('/?id=' ,"", $_SERVER['REQUEST_URI']) : 0;
It was used when the URL is http://www.testing.com/?id=123
当 URL 为 http://www.testing.com/?id=123
But now I wanna pass 1 more variable in url string http://www.testing.com/?id=123&othervar=123
但是现在我想在 url 字符串中再传递 1 个变量 http://www.testing.com/?id=123&othervar=123
how should I change the code above to retrieve both variable?
我应该如何更改上面的代码以检索两个变量？
回答by nand
You can either use regex, or keep on using str_replace.
您可以使用正则表达式，也可以继续使用str_replace.
Eg.
例如。
$url = parse_url($_SERVER['REQUEST_URI']);
if ($url != '/') {
parse_str($url['query']);
echo $id;
echo $othervar;
}
Output will be: http://www.testing.com/123/123
回答by Oldskool
回答by cyberseppo
perhaps
也许
$id = isset($_GET['id'])?$_GET['id']:null;
and
和
$other_var = isset($_GET['othervar'])?$_GET['othervar']:null;
回答by ???? ??????
You can simply use $_GETespecially if you know the othervar's name.
If you want to be on the safe side, use if (isset ($_GET ['varname']))to test for existence.
您可以简单地使用，$_GET特别是如果您知道othervar的名称。如果您想安全起见，请使用if (isset ($_GET ['varname']))来测试是否存在。
回答by Sergio
Since vars passed through url are $_GET vars, you can use filter_input()function:
由于通过 url 传递的变量是 $_GET 变量，您可以使用filter_input()函数：
$id = filter_input(INPUT_GET, 'id', FILTER_SANITIZE_NUMBER_INT);
$othervar = filter_input(INPUT_GET, 'othervar', FILTER_SANITIZE_FULL_SPECIAL_CHARS);
It would store the values of each var and sanitize/validate them too.
它将存储每个 var 的值并清理/验证它们。
