Linux 在 bash 中设置 wget --header= 不起作用
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Setting wget --header= in bash doesn't work
提问by rabotalius
I trying to set header in wget. When I run the following command in terminal it works wget -d --header="User-Agent: Mozilla/5.0 (Windows NT 6.0) AppleWebKit/537.11 (KHTML, like Gecko) Chrome/23.0.1271.97 Safari/537.11"' http://website.com -O index
我试图在 wget 中设置标题。当我在终端中运行以下命令时，它可以工作wget -d --header="User-Agent: Mozilla/5.0 (Windows NT 6.0) AppleWebKit/537.11 (KHTML, like Gecko) Chrome/23.0.1271.97 Safari/537.11"' http://website.com -O index
but once i put the same in variables and try to run a bash script it's not working.
但是一旦我将相同的变量放在变量中并尝试运行 bash 脚本，它就不起作用了。
what i've tried
我试过的
header='-d --header="User-Agent: Mozilla/5.0 (Windows NT 6.0) AppleWebKit/537.11 (KHTML, like Gecko) Chrome/23.0.1271.97 Safari/537.11"'
wget "$header" http://google.com -O index
error
错误
wget: invalid option -- ' '
wget: invalid option -- '-'
wget: invalid option -- '-'
Usage: wget [OPTION]... [URL]...
回答by nosid
You have to use double quotes when using the variable. Otherwise it will be expanded into multiple words. On the other hand, there is no need to quote the variable value twice. The following should work:
使用变量时必须使用双引号。否则它会被扩展为多个单词。另一方面，不需要两次引用变量值。以下应该工作：
header='--header=User-Agent: Mozilla/5.0 (Windows NT 6.0) AppleWebKit/537.11 (KHTML, like Gecko) Chrome/23.0.1271.97 Safari/537.11'
wget "$header" http://website.com -O index
Edit:If you want to use variables for several arguments, use arrays:
编辑：如果要对多个参数使用变量，请使用数组：
args=(-d '--header=User-Agent: Mozilla/5.0 (Windows NT 6.0) AppleWebKit/537.11 (KHTML, like Gecko) Chrome/23.0.1271.97 Safari/537.11')
wget "${args[@]}" http://website.com -O index
回答by SSaikia_JtheRocker
Instead of this
而不是这个
wget $header http://website.com -O index
try this,
尝试这个，
wget "$header" http://website.com -O index
The spaces in the header text is breaking up when you are assigning it the header variable. To do away with the problem you must surround a variable with quotes "".
当您将标题变量分配给标题文本时，标题文本中的空格会破裂。要解决这个问题，您必须用引号 "" 将变量括起来。
After comments:Try this -
评论后：试试这个 -
someheader="-d --header='User-Agent: Mozilla/5.0 (Windows NT 6.0) AppleWebKit/537.11 (KHTML, like Gecko) Chrome/23.0.1271.97 Safari/537.11'"
wget "$someheader" http://website.com -O index
The name header seems conflicting with your --header. Or, may be the quotes, instead of copying type them and retry. Still, Weird!
名称标题似乎与您的 --header 冲突。或者，可能是引号，而不是复制它们并重试。还是，怪！
回答by WxWizard
COMMENT: 'nosid's trick about the bash array worked for me. In my case the relevant code is:
评论：'nosid 关于 bash 数组的技巧对我有用。就我而言，相关代码是：
WGET_OPTS="-r -N -nd -np -nH --timeout=120 --tries=3"
WGET_OPTS_ARRAY=(${WGET_OPTS// / })
wget "${WGET_OPTS_ARRAY[@]}" -A "$FILE_PAT" -P "$TO_DIR" "$FROM_URL"
回答by Michael Meepo
What you only need to do is to escape -dlike this:
header='\-d --header="User-Agent: Mozilla/5.0 (Windows NT 6.0) AppleWebKit/537.11 (KHTML, like Gecko) Chrome/23.0.1271.97 Safari/537.11"'
你只需要-d像这样逃跑：
header='\-d --header="User-Agent: Mozilla/5.0 (Windows NT 6.0) AppleWebKit/537.11 (KHTML, like Gecko) Chrome/23.0.1271.97 Safari/537.11"'
