ios URL 编码字符串
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URL Encoding a string
提问by B.I.A
i am receiving a json data object and then i extract a string from it
我正在接收一个 json 数据对象，然后我从中提取一个字符串
NSDictionary *jsonDictionary = [NSJSONSerialization JSONObjectWithData:data
options:0
error:nil];
NSString *country=jsonDictionary[@"address"][@"country"];
then i try to make the string suitable to be used in a URL
然后我尝试使字符串适合在 URL 中使用
NSString *newCountryString = [country stringByReplacingOccurrencesOfString:@" "
withString:@"%%20"];
but it is not working
但它不起作用
if i hard coded the newCountryString it would work, why is that ?
如果我对 newCountryString 进行硬编码它会起作用，为什么会这样？
回答by Akshay Nalawade
Use This -
用这个 -
NSString *newCountryString = [country stringByAddingPercentEscapesUsingEncoding:NSUTF8StringEncoding];
This code will return a representation of the receiver using a given encoding to determine the percent escapes necessary to convert the receiver into a legal URL string.
此代码将使用给定的编码返回接收器的表示，以确定将接收器转换为合法 URL 字符串所需的转义百分比。
for more details: https://developer.apple.com/documentation/foundation/nsstring/1415058-stringbyaddingpercentescapesusin
更多详情：https: //developer.apple.com/documentation/foundation/nsstring/1415058-stringbyaddingpercentescapesusin
Edit -stringByAddingPercentEscapesUsingEncoding is deprecated in iOS 9. Use following instead
编辑 -stringByAddingPercentEscapesUsingEncoding 在 iOS 9 中已弃用。请改用以下内容
[country stringByAddingPercentEncodingWithAllowedCharacters:[NSCharacterSet URLHostAllowedCharacterSet]]
Swift 3 -
斯威夫特 3 -
country.addingPercentEncoding( withAllowedCharacters: .urlHostAllowed)
for more details: https://developer.apple.com/documentation/foundation/nsstring/1411946-stringbyaddingpercentencodingwit?language=objc
更多详情：https: //developer.apple.com/documentation/foundation/nsstring/1411946-stringbyaddingpercentencodingwit?language=objc
回答by Ruslan Soldatenko
As variant you can use method below:
作为变体，您可以使用以下方法：
- (NSString *)URLEncodeStringFromString:(NSString *)string
{
static CFStringRef charset = CFSTR("!@#$%&*()+'\";:=,/?[] ");
CFStringRef str = (__bridge CFStringRef)string;
CFStringEncoding encoding = kCFStringEncodingUTF8;
return (NSString *)CFBridgingRelease(CFURLCreateStringByAddingPercentEscapes(NULL, str, NULL, charset, encoding));
}
回答by Volker
The NSSString method stringByAddingPercentEscapesUsingEncoding should help you. Also see How to prepare an NSURL from an NSString continaing international characters?
NSSString 方法 stringByAddingPercentEscapesUsingEncoding 应该可以帮助您。另请参阅如何从包含国际字符的 NSString 准备 NSURL？
回答by Sean Dey
I think you should remove one % like below
我认为你应该删除 1%，如下所示
NSString *newCountryString = [country stringByReplacingOccurrencesOfString:@" " withString:@"%20"];
for more
更多
NSMutableString stringByReplacingOccurrencesOfString Warning
