C语言 获取 C 字符串中索引引用的字符
声明：本页面是StackOverFlow热门问题的中英对照翻译，遵循CC BY-SA 4.0协议，如果您需要使用它，必须同样遵循CC BY-SA许可，注明原文地址和作者信息，同时你必须将它归于原作者（不是我）：StackOverFlow
原文地址: http://stackoverflow.com/questions/4475948/
Warning: these are provided under cc-by-sa 4.0 license. You are free to use/share it, But you must attribute it to the original authors (not me):
StackOverFlow
Get a character referenced by index in a C string
提问by Honza Pokorny
I have a string.
我有一个字符串。
char foo[] = "abcdefgh";
I would like to write a forloop, and one by one print out all of the characters:
我想写一个for循环，把所有的字符一一打印出来：
a
b
c
etc.
等等。
This is in C.
这是在 C 中。
回答by
Ok, well, this is a question so I'm going to answer it, but my answer is going to be slightly unusual:
好吧，这是一个问题，所以我要回答它，但我的回答会有点不寻常：
#include <stdio.h>
int main(int argc, char** argv)
{
char string[] = "abcdefghi";
char* s;
for ( s=&string[0]; *s != 'void main(int argc, char** argv)
{
char foo[] = "abcdefgh";
int len = strlen(foo);
int i = 0;
for (i=0; i < len; i++)
{
printf("%c\n", foo[i]);
}
return 0;
}
'; s++ )
{
printf("%c\n", *s);
}
return 0;
}
This is notthe simplest way to achieve the desired outcome; however, it does demonstrate the fundamentals of what a string is in C. I shall leave you to read up on what I've done and why.
这不是实现预期结果的最简单方法；然而，它确实展示了 C 中字符串的基本原理。我会让你阅读我所做的以及为什么。
回答by Honza Pokorny
int main(int argc, char *argv[])
{
char foo[] = "abcdefgh";
int len = sizeof(foo)/sizeof(char);
int i = 0;
for (i=0; i < len; i++) {
printf("%c\n", foo[i]);
}
return 0;
}
回答by Nick Masao
Yet another way
又一种方式
##代码##