我如何将一个数字与 Javascript 中的一系列数字进行比较？
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How would I compare a number to a range of numbers in Javascript?
提问by Ryan S.
I want to compare a range of numbers against a single number, basically like this in simple terms:
我想将一系列数字与单个数字进行比较，简单来说基本上是这样的：
if X through Y equals Z, then do {}
What would be the proper way to do something like that in Javascript?
在 Javascript 中执行类似操作的正确方法是什么？
CLARIFICATION
澄清
I want to check if any number between X and Yis equal to Z
我想检查之间的任何数字X and Y是否等于Z
Edit
编辑
I'm not sure why the down-votes, I had a legitimate question.
我不确定为什么投反对票，我有一个合理的问题。
回答by Daniel Moses
A range doesn't equal a number, do you mean that the number falls within the range?
一个范围不等于一个数字，你的意思是这个数字在这个范围内吗？
if (1 <= Z && Z <= 25 ) {
foo();
}
回答by Jon Newmuis
If you want to determine if Zis inthe range [X, Y], then you can do:
如果要确定是否Z是在该范围内[X, Y]，那么你可以这样做：
if (X < Z && Z < Y) {
// do stuff.
}
Otherwise, a range can't equal a number.
否则，范围不能等于数字。
回答by Adam Rackis
To check if elements 1 through 3 are all 1:
要检查元素 1 到 3 是否都是 1：
var arr = [0, 1, 1, 1, 2];
var allOne = arr.slice(1, 4).filter(
function(val) { return val !== 1; }).length === 0;
EDIT
编辑
Even better, thanks to @am not i am
更好的是，感谢 @am not i am
var arr = [0, 1, 1, 1, 2];
var allOne = arr.slice(1, 4).every(function (val) { return val === 1; });
回答by ziesemer
var arr = [...];
var compareRange = function(arr, x, y, z){
for(var i=x; i<=y; i++){
if(arr[i] != z){
return false;
}
}
return true;
};
回答by Tristian
First the range function:
首先是范围函数：
function range(a,b){
var r = [a];
for(var i=a;i<=b;i++){
r.push(i);
}
return r;
}
Now use the function and make the comparison:
现在使用该函数并进行比较：
var a = range(1,6); // Range
var z = 7;
if(a.indexOf(z) > -1){
// Collision !!!
}else{
// No collision, I suppose...
}
