C# 减去时间（小时分钟）
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C# subtract time (hours minutes)
提问by Audrius Gr
Hello Everyone I have some interesting situation.
大家好 我有一些有趣的情况。
I want to count how many hours (in minutes) is from 20:00 to 01:00 AM, but i Don't know how, because what i have done is:
我想计算从 20:00 到 01:00 AM 有多少小时（以分钟为单位），但我不知道如何，因为我所做的是：
pabaigosLaikoLaukelis = 01:00;
pradziosLaikoLaukelis = 20:00;
TimeSpan dt = Convert.ToDateTime(pabaigosLaikoLaukelis)- Convert.ToDateTime(pradziosLaikoLaukelis);
int minutes = (int)dt.TotalMinutes;
And i get result -> -1140 minutes, but I need that answer to be just 5 hours from 20:00 to 01:00.
我得到结果 -> -1140 分钟，但我需要这个答案是从 20:00 到 01:00 只有 5 小时。
I know that it is quite easy, but i have no idea how to do it.
我知道这很容易，但我不知道该怎么做。
采纳答案by Thomas Andreè Wang
you could do something like this
你可以做这样的事情
//Datetime(Year,month,day,hour,min,sec)
DateTime date1 = new DateTime(2012, 1, 1, 20, 0, 0);
DateTime date2 = new DateTime(2012, 1, 2, 1, 0, 0);
string minutes = (date2.Subtract(date1).TotalMinutes).ToString();
Tested and works 300 minutes (5 hours)
测试并工作 300 分钟（5 小时）
回答by Rob
You need to specify the Day, you are subracting (Today 1:00 AM) - (Today 8:00 PM)
您需要指定日期，您正在减法（今天上午 1:00） - （今天下午 8:00）
I think you need to subract (Tommorrow 1:00 AM) - (Today 8:00 PM)
我认为你需要减去 (Tomorrow 1:00 AM) - (Today 8:00 PM)
回答by Andrii Kalytiiuk
Use full date time strings that contain day part, to show that 01:00 AM is one day later than 20:00 - like following:
使用包含日期部分的完整日期时间字符串，以显示 01:00 AM 比 20:00 晚一天 - 如下所示：
int minutes = Convert.ToDateTime("01/02/2012 01:00").Substract(Convert.ToDateTime("01/01/2012 20:00")).TotalMinutes;
回答by Dustin Kingen
You need to add a day to the first TimeSpanand use TotalHours.
您需要在第一天添加一天TimeSpan并使用TotalHours.
var pabaigosLaikoLaukelis = "01:00";
var pradziosLaikoLaukelis = "20:00";
var oneDayTimeSpan = new TimeSpan(1, 0, 0, 0);
TimeSpan dt = TimeSpan.Parse(pabaigosLaikoLaukelis).Add(oneDayTimeSpan) - TimeSpan.Parse(pradziosLaikoLaukelis);
int minutes = (int)dt.TotalHours; // 5 hours
Using associative operations:
使用关联操作：
var pabaigosLaikoLaukelis = "21:00";
var pradziosLaikoLaukelis = "20:00";
var leftHours = (int)TimeSpan.Parse(pabaigosLaikoLaukelis).TotalHours;
var rightHours = (int)TimeSpan.Parse(pradziosLaikoLaukelis).TotalHours;
// Now we do a Modulus operation which will assure
// 23 > hours > 0
// Make sure to check that leftHours != 0 or rightHours != 0
int hours = (Math.Abs(leftHours * rightHours) + leftHours) % rightHours; //Modulus
var hoursTimeSpan = TimeSpan.FromHours(hours);
回答by Julián Urbano
Be careful with adding one day to the endTime, because then the difference between 20:00 and 22:00 will be 26 hours instead of 2!
将一天添加到 endTime 时要小心，因为那样 20:00 和 22:00 之间的差异将是 26 小时而不是 2 小时！
Just check whether the difference is positive (same day) or negative (next day)
只需检查差异是正（当天）还是负（第二天）
string pabaigosLaikoLaukelis = "01:00";
string pradziosLaikoLaukelis = "20:00";
// This should be 5 hours
TimeSpan dt = Convert.ToDateTime(pabaigosLaikoLaukelis) - Convert.ToDateTime(pradziosLaikoLaukelis);
int hours = (int)dt.TotalHours;
hours = hours < 0 ? 24 + hours : hours;
// This should be 19 hours
dt = Convert.ToDateTime(pradziosLaikoLaukelis) - Convert.ToDateTime(pabaigosLaikoLaukelis);
hours = (int)dt.TotalHours;
hours = hours < 0 ? 24 + hours : hours;
回答by Steve
A bit of preparation of the two string variables is required before attempting data calculations
在尝试数据计算之前需要对两个字符串变量进行一些准备
string pabaigosLaikoLaukelis = "01:00";
string pradziosLaikoLaukelis = "20:00";
pabaigosLaikoLaukelis = DateTime.Today.ToString("dd/MM/yyyy") + " " + pabaigosLaikoLaukelis;
pradziosLaikoLaukelis = DateTime.Today.AddDays(-1).ToString("dd/MM/yyyy") + " " + pradziosLaikoLaukelis;
TimeSpan dt = Convert.ToDateTime(pabaigosLaikoLaukelis) - Convert.ToDateTime(pradziosLaikoLaukelis);
Console.WriteLine("{0:D2}:{1:D2}", dt.Hours, dt.Minutes);
回答by Ozan Kaya
How about this:
这个怎么样：
pabaigosLaikoLaukelis = 01:00;
pradziosLaikoLaukelis = 20:00;
TimeSpan startTime = Convert.ToDateTime(pradziosLaikoLaukelis).TimeOfDay;
TimeSpan endTime = Convert.ToDateTime(pabaigosLaikoLaukelis).TimeOfDay;
TimeSpan diff = endTime > startTime ? endTime - startTime : endTime - startTime + TimeSpan.FromDays(1);
int minutes = (int)diff.TotalMinutes;
