bash Makefile 错误退出并显示一条消息
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Makefile error exit with a message
提问by Basile Starynkevitch
Is there any way to output a error message when the error happens.Let's go into details,I want to know whether one file content equal to another or not.If not ,makeshould exit and output a error message.
有没有什么方法可以在错误发生时输出错误信息。详细说一下，我想知道一个文件内容是否等于另一个文件内容。如果不是，make应该退出并输出错误信息。
test:
cmp --silent tmp/test.txt tmp/test_de.txt || (error DecryptFile is different from original)
When tmp/test.txtdoes not equal to tmp/test_de.txt,the output is:
当tmp/test.txt不等于时tmp/test_de.txt，输出为：
cmp --silent tmp/test.txt tmp/test_de.txt | (error DecryptFile is different from original)
/bin/sh: 1: error: not found
makefile:38: recipe for target 'test' failed
make: *** [test] Error 127
/bin/sh: 1: error: not found
/bin/sh: 1: 错误：未找到
The result isn't what I want.I just want like this kind of error message:
结果不是我想要的。我只是想要这样的错误信息：
makefile:38: *** missing separator. Stop.
回答by torbatamas
You can use exit. the (and )can enclose more than one command:
您可以使用exit. 的(和)能够包围一个以上的命令：
cmp --silent tmp/test.txt tmp/test_de.txt || (echo "DecryptFile is different from original"; exit 1)
回答by Basile Starynkevitch
Perhaps the errorrefers to the GNU Make built-in error functionbut then you should write $(error....)instead of just (error....)and you cannot use it that way (in a shell command). So you really should use echoand exitas answered by tobatamas. Perhaps you might redirect the echoto stderr(e.g. echo message 2>&1or echo message > /dev/stderr)
也许error指的是GNU Make 内置错误函数，但是您应该编写$(error....)而不仅仅是(error....)并且您不能那样使用它（在 shell 命令中）。所以，你真的应该使用echo，并exit作为由tobatamas回答。也许您可能会将其重定向echo到stderr（例如echo message 2>&1或echo message > /dev/stderr）
The $(error....)builtin could be (and often is) used with GNU make conditionals.
该$(error....)是GNU make使用内置的可能是（而且经常是）条件语句。
