bash X 分钟后脚本重复自身

Script repeat itself after X minutes

提问by Aaron

I have a bash script in Ubuntu, I want it to run every 10 minutes for example after it's done. How can I do this? Thanks!

我在 Ubuntu 中有一个 bash 脚本，我希望它在完成后每 10 分钟运行一次。我怎样才能做到这一点？谢谢！

回答by another.anon.coward

You can check watch.
From the man pages of watchthe description says watch - execute a program periodically, showing output fullscreen, you can try watch -n 600 my_script.shwhich will execute myscript.shevery 600 seconds i.e. 10 minutes. watchshows the output to full screen, you can redirect it to say /dev/nullin case you are not interested in the output to the screen.
Hope this helps!

你可以检查watch。
从描述的手册页中watchwatch - execute a program periodically, showing output fullscreen可以看出，您可以尝试每 600 秒watch -n 600 my_script.sh执行myscript.sh一次，即 10 分钟。watch将输出显示为全屏，/dev/null如果您对输出到屏幕不感兴趣，您可以将其重定向。
希望这可以帮助！

回答by Abhijeet Rastogi

Cronjobs is what you need.

Cronjobs 正是您所需要的。

My blog post:- http://linux-junky.blogspot.com/2010/10/guide-to-add-cronjob-simplified.html

我的博文：- http://linux-junky.blogspot.com/2010/10/guide-to-add-cronjob-simplified.html

Or you can also use sleep 600in your script.

或者您也可以在脚本中使用sleep 600。

回答by glenn Hymanman

You can use atto reschedule the script from within the script. At the end of the script put:

您可以使用at从脚本内重新安排脚本。在脚本的末尾放置：

at now + 10 minutes << END
"
if [ $((`date +%M`%10)) -eq 0 ] && [ `date +%S` -lt 10 ]; then
   #your code
fi
" "$@"
END

回答by Refael

Or with crontab -e, or another option, to check the date. for example, if you want to do something every 10 minutes, you can write:

或者使用 crontab -e 或其他选项来检查日期。例如，如果你想每 10 分钟做一件事，你可以这样写：

##代码##