Python 如何从数据框的索引中获取行的名称？
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How do I get the name of the rows from the index of a data frame?
提问by linamnt
Consider a data frame with row names that aren't a column of their own per se, such as the following:
考虑一个数据框，其行名称本身不是一列，例如以下内容：
X Y
Row 1 0 5
Row 2 8 1
Row 3 3 0
How would I extract the name of these rows as a list, if I have their index? For example, it would look something like:
如果我有它们的索引，我将如何将这些行的名称提取为列表？例如，它看起来像：
function_name(dataframe[indices])
> ['Row 1', 'Row 2']
采纳答案by Adam Hughes
df.index
df.index
- outputs the row names as pandas
Indexobject.
- 将行名称输出为 pandas
Index对象。
list(df.index)
list(df.index)
- casts to a list.
- 强制转换为列表。
df.index['Row 2':'Row 5']
df.index['Row 2':'Row 5']
- supports label slicing similar to columns.
- 支持类似于列的标签切片。
回答by heyitschun
if you want to get the index values, you can simply do:
如果要获取索引值，只需执行以下操作：
dataframe.index
数据框索引
this will output a pandas.core.index
这将输出一个 pandas.core.index
回答by K Raphael
If you want to pull out only the index values for certain integer-based row-indices, you can do something like the following using the ilocmethod:
如果您只想提取某些基于整数的行索引的索引值，您可以使用该iloc方法执行以下操作：
In [28]: temp
Out[28]:
index time complete
row_0 2 2014-10-22 01:00:00 0
row_1 3 2014-10-23 14:00:00 0
row_2 4 2014-10-26 08:00:00 0
row_3 5 2014-10-26 10:00:00 0
row_4 6 2014-10-26 11:00:00 0
In [29]: temp.iloc[[0,1,4]].index
Out[29]: Index([u'row_0', u'row_1', u'row_4'], dtype='object')
In [30]: temp.iloc[[0,1,4]].index.tolist()
Out[30]: ['row_0', 'row_1', 'row_4']
回答by Alex Kushkuley
this seems to work fine :
这似乎工作正常：
dataframe.axes[0].tolist()
