C++ 字符串变量声明

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时间:2020-08-28 16:19:56  来源:igfitidea点击:

C++ String Variable Declaration

c++stringvariablesdeclaration

提问by Mike

I'm having some trouble declaring a string variable. Code and the errors are here: http://pastebin.com/TEQCxpZdAny thoughts on what I'm doing wrong? Also, please keep it platform independent. Thanks!

我在声明字符串变量时遇到了一些麻烦。代码和错误在这里:http://pastebin.com/TEQCxpZd 关于我做错了什么的任何想法?另外,请保持平台独立。谢谢!

#include <stdio.h>
#include <string>
using namespace std;

int main()
{
    string input; //Declare variable holding a string

    input = scanf; //Get input and assign it to variable
    printf(input); //Print text
    return 0;
}


Getting this from GCC:

main.cpp: In function ‘int main()':
main.cpp:53:10: error: invalid conversion from ‘int (*)(const char*, ...)' to ‘char'
main.cpp:53:10: error:   initializing argument 1 of ‘std::basic_string<_CharT, _Traits, _Alloc>& std::basic_string<_CharT, _Traits, _Alloc>::operator=(_CharT) [with _CharT = char, _Traits = std::char_traits<char>, _Alloc = std::allocator<char>, std::basic_string<_CharT, _Traits, _Alloc> = std::basic_string<char>]'
main.cpp:54:14: error: cannot convert ‘std::string' to ‘const char*' for argument ‘1' to ‘int printf(const char*, ...)'

回答by Naveen

You are mixing c++ and c I/O. In C++ this is,

您正在混合 c++ 和 c I/O。在 C++ 中,这是,

#include <string>
#include <iostream>

int main(void)
{
   std::string input;
   std::cin >> input;
   std::cout << input;
   return 0;
 }

回答by dan04

cannot convert ‘std::string' to ‘const char*' for argument ‘1' to ‘int printf(const char*, ...)'

无法将参数 '1' 的 'std::string' 转换为 'const char*' 到 'int printf(const char*, ...)'

input = scanf; //Get input and assign it to variable

You're trying to assign the function pointerto scanfto a string variable. You can't do that, which is why you're getting the first error. The proper syntax would be.

你试图将分配函数指针scanf一个字符串变量。你不能那样做,这就是你得到第一个错误的原因。正确的语法是。

char buffer[BIG_ENOUGH_SIZE];
scanf("%*s", sizeof(buffer) - 1, buffer);
input = buffer;

But that's a very C-style way of doing things. The idiomatic way to read input in C++ is with std::cin >> inputas Nathan suggested.

但这是一种非常 C 风格的做事方式。在 C++ 中读取输入的惯用方法是与std::cin >> inputNathan 建议的一样。

cannot convert ‘std::string' to ‘const char*' for argument ‘1' to ‘int printf(const char*, ...)'

无法将参数 '1' 的 'std::string' 转换为 'const char*' 到 'int printf(const char*, ...)'

printf(input); //Print text

printftakes a const char*as its first argument, not a std::string. You can use .c_str()to convert to a C-style string. But neverpass user input as the first argument to printf; the user can do nasty stuff by putting %'s in the string. If you insist on C-style output, the correct syntax is:

printf将 aconst char*作为它的第一个参数,而不是 a std::string。您可以使用.c_str()转换为 C 风格的字符串。但永远不要将用户输入作为第一个参数传递给printf; 用户可以通过将%'s 放在字符串中来做讨厌的事情。如果你坚持 C 风格的输出,正确的语法是:

printf("%s", input.c_str());

But the C++-style alternative is std::cout << input;.

但是 C++ 风格的替代方案是std::cout << input;.

回答by dan04

I understand the question to be: How do you make a string declaration in C++? Here's a short program to demonstrate:

我理解的问题是:如何在 C++ 中进行字符串声明?这是一个简短的程序来演示:

#include<iostream>
#include<cstdlib>
using namespace std;
int main()
{
    string your_name;
    cout << "Enter your name: ";
    cin >> your_name;
    cout << "Hi, " << your_name << "!\n";
    return 0;
}

So, include cstdlib at the start of your program. In practical terms, this means typing string instead of std::string, cout instead of std::cout and so on. The string variable itself (in the example, the string variable is your_name) is declared with string.

因此,在程序开始时包含 cstdlib。实际上,这意味着键入 string 而不是 std::string,cout 而不是 std::cout 等等。字符串变量本身(在示例中,字符串变量是 your_name)是用字符串声明的。

Let's say you've saved the program with the filename, 'str_example.cpp' To compile the program at the command line (in Linux):

假设您已使用文件名“str_example.cpp”保存程序,以在命令行(在 Linux 中)编译该程序:

g++ -o str_example str_example.cpp

This creates an executable object file called str_example (no file extension). And finally, assuming you're in the same directory as the program, to run it:

这将创建一个名为 str_example(无文件扩展名)的可执行对象文件。最后,假设你和程序在同一个目录下,运行它:

./str_example

The man page for g++ is extensive but not included by default. To install g++ documentation using the aptitude package manager:

g++ 的手册页很广泛,但默认情况下不包含在内。使用 aptitude 包管理器安装 g++ 文档:

sudo apt-get install gcc-7-doc

Note that the '7' refers to version 7; the current version at the time of writing. Hope that helps.

请注意,“7”指的是版本 7;撰写本文时的当前版本。希望有帮助。