Laravel 5.2 验证错误未出现
声明:本页面是StackOverFlow热门问题的中英对照翻译,遵循CC BY-SA 4.0协议,如果您需要使用它,必须同样遵循CC BY-SA许可,注明原文地址和作者信息,同时你必须将它归于原作者(不是我):StackOverFlow
原文地址: http://stackoverflow.com/questions/34888232/
Warning: these are provided under cc-by-sa 4.0 license. You are free to use/share it, But you must attribute it to the original authors (not me):
StackOverFlow
Laravel 5.2 validation errors not appearing
提问by user1072337
I am trying to get validation errors to show up in Laravel.
我试图让验证错误显示在 Laravel 中。
I have a UserController set up like so:
我有一个 UserController 设置如下:
<?php
namespace App\Http\Controllers;
use App\User;
use App\Http\Controllers\Controller;
//Use Request;
Use Flash;
Use Illuminate\Http\Request;
class UserController extends Controller
{
/**
* Show the profile for the given user.
*
* @param int $id
* @return Response
*/
public function showProfile($id)
{
return view('user.profile', ['user' => User::findOrFail($id)]);
}
public function store(Request $request) {
$this->validate($request, [
'email' => 'required|unique:users|email|max:255',
]);
if($this) {
$input = Request::all();
User::create($input);
return redirect('/');
}
else {
return redirect('/')->withErrors($validator);
}
}
}
In my view (layout.blade.php), I have included:
在我看来(layout.blade.php),我已经包括:
@if (count($errors) > 0)
@foreach ($errors->all() as $error)
{{!! $errors !!}}
@endforeach
@endif
To account for the route, I have:
为了说明路线,我有:
Route::group(['middleware' => ['web']], function () {
Route::get('/', function (){
return view('home');
});
});
Unfortunately, when I enter "bad" data that shouldn't be verified, I am not seeing any error (but it is not being stored in the db, so there's that).
不幸的是,当我输入不应验证的“坏”数据时,我没有看到任何错误(但它没有存储在数据库中,所以就是这样)。
One other note, when the blade template is rendered, I am seeing an extra "}" bracket, which I'm not sure why that is there.
另一个注意事项是,当渲染刀片模板时,我看到一个额外的“}”括号,我不确定为什么会出现这种情况。
回答by Mirza Vu
In laravel version 5.2.41, the middleware web is thrown out.
在 laravel 5.2.41 版本中,中间件 web 被抛弃了。
Means adding the routes inside Route::group(['middleware' => ['web']], function () {
will make the validation not work.
意味着在里面添加路由Route::group(['middleware' => ['web']], function () {
会使验证不起作用。
回答by Logan Bailey
There are a couple things wrong or that can be improved here. The store method on the UserController has a lot of weird issues. $this
will always be true because objects are true in php. Also, you pass in $validator
into withErrors
which doesn't make sense because there's no variable validator
.
有几件事是错误的,或者可以在这里改进。UserController 上的 store 方法有很多奇怪的问题。$this
将始终为真,因为对象在 php 中为真。此外,您传递$validator
到withErrors
其中没有任何意义,因为没有变量validator
。
public function store(Request $request) {
$this->validate($request, [
'email' => 'required|unique:users|email|max:255',
]);
User::create(Request::all());
return redirect('/');
}
The validate
method will throw an Illuminate\Foundation\Validation\ValidationException
if there is a validation error. This exception should be listed in the $dontReport
instance variable in App\Exceptions\Handler
as seen below:
如果存在验证错误,该validate
方法将抛出一个Illuminate\Foundation\Validation\ValidationException
。此异常应列在$dontReport
实例变量中App\Exceptions\Handler
,如下所示:
protected $dontReport = [
AuthorizationException::class,
HttpException::class,
ModelNotFoundException::class,
ValidationException::class,
];
If you have changed these values, removed, or modified the ValidatesRequest
trait you may have broken this functionality.
如果您更改了这些值、删除或修改了ValidatesRequest
特征,则您可能破坏了此功能。
Your error reporting code is not correct either:
您的错误报告代码也不正确:
@foreach ($errors->all() as $error)
{!! $errors->first() !!}
@endforeach
There are 3 changes here. First I removed the outer errors size check, this doesn't really get you anything. Next, I fixed your extra }
error, the syntax for un-escaping data is {!! $errors->first() !!}
. Lastly, I called ->first()
this returns the first error associated with that particular field.
这里有3个变化。首先,我删除了外部错误大小检查,这并没有真正为您提供任何帮助。接下来,我修复了您的额外}
错误,非转义数据的语法是{!! $errors->first() !!}
. 最后,我称之为->first()
返回与该特定字段关联的第一个错误。
I think it's important to note that the validation exception will create a redirect response to the previous page. The logic for determining the previous page can be found in Illuminate\Routing\UrlGenerator::previous()
.
我认为重要的是要注意验证异常将创建到上一页的重定向响应。可以在 中找到确定上一页的逻辑Illuminate\Routing\UrlGenerator::previous()
。
回答by Chris
The errors block should be:
错误块应该是:
@if (count($errors) > 0)
<div class="alert alert-danger">
<ul>
@foreach ($errors->all() as $error)
<li>{{ $error }}</li>
@endforeach
</ul>
</div>
@endif
Assuming you're using Bootstrap for the alerts.
假设您使用 Bootstrap 来发送警报。
You also don't have $validator
defined. You need to do something like this:
你也没有$validator
定义。你需要做这样的事情:
$validator = Validator::make($request->all(), [
'email' => 'required|unique:users|email|max:255',
]);
Instead of $this->validate()
.
而不是$this->validate()
.
That should do it.
那应该这样做。
回答by Musthafa Ma
@if(count(($errors->all()) > 0))
@foreach($errors->all() as $error)
<div class="alert alert-danger">
{{$error}}
</div>
@endforeach
@endif