C++ 如何将文件系统路径转换为字符串
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how to convert filesystem path to string
提问by anonymous noob
I am iterating through all the files in a folder and just want their names in a string. I want to get a string from a std::filesystem::path. How do I do that?
我正在遍历文件夹中的所有文件，只想将它们的名称放在一个字符串中。我想从std::filesystem::path. 我怎么做？
My code:
我的代码：
#include <string>
#include <iostream>
#include <filesystem>
namespace fs = std::experimental::filesystem;
int main()
{
std::string path = "C:/Users/user1/Desktop";
for (auto & p : fs::directory_iterator(path))
std::string fileName = p.path;
}
However I get the following error:
但是我收到以下错误：
non-standard syntax; use '&' to create a pointer to a member.
回答by tambre
To convert a std::filesystem::pathto a natively-encoded string (whose type is std::filesystem::path::value_type), use the string()method. Note the other *string()methods, which enable you to obtain strings of a specific encoding (e.g. u8string()for an UTF-8 string).
要将 a 转换std::filesystem::path为本地编码的字符串（其类型为std::filesystem::path::value_type），请使用string()方法。请注意其他*string()方法，它们使您能够获取特定编码的字符串（例如u8string()，对于 UTF-8 字符串）。
C++17 example:
C++17 示例：
#include <filesystem>
#include <string>
namespace fs = std::filesystem;
int main()
{
fs::path path = fs::u8path(u8"愛.txt");
std::string path_string = path.u8string();
}
C++20 example (better language and library UTF-8 support):
C++20 示例（更好的语言和库 UTF-8 支持）：
#include <filesystem>
#include <string>
namespace fs = std::filesystem;
int main()
{
fs::path path{u8"愛.txt"};
std::u8string path_string = path.u8string();
}
