ios 如何在 Swift 中发送 POST 参数?

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时间:2020-08-31 01:21:49  来源:igfitidea点击:

How to send POST parameters in Swift?

iosswift

提问by Maxim Tsybanov

Here some code:

这里有一些代码:

var URL: NSURL = NSURL(string: "http://stackoverflow.com")
var request:NSMutableURLRequest = NSMutableURLRequest(URL:URL)
request.HTTPMethod = "POST"
request.HTTPBody = ?????? 
NSURLConnection.sendAsynchronousRequest(request, queue: NSOperationQueue.mainQueue()) 
{
    (response, data, error) in
    println(NSString(data: data, encoding: NSUTF8StringEncoding))
}

What should I write in request.HTTPBodyif I want send POST query "key" = "value"?

request.HTTPBody如果我想发送 POST 查询,我应该写什么"key" = "value"

回答by pixel

No different than in Objective-C, HTTPBody expects an NSData object:

与 Objective-C 没有什么不同,HTTPBody 需要一个 NSData 对象:

var bodyData = "key1=value&key2=value&key3=value"
request.HTTPBody = bodyData.dataUsingEncoding(NSUTF8StringEncoding);

You'll have to setup the values & keys yourself in the string.

您必须自己在字符串中设置值和键。

回答by Ishwar Hingu

class func postMethod (params: [String : AnyObject], apikey: String, completion: @escaping (Any) -> Void, failure:@escaping (Error) -> Void)
{
    if Utils().isConnectedToNetwork() == false
    {
        DispatchQueue.main.asyncAfter(deadline: .now() + 0.1, execute: {
            Utils().HideLoader()
        })
        return
    }

    let strURL = Constants.BASE_URL + apikey
    let url = URL(string: strURL)
    print(params)
    print(strURL)

    var token = String()

    if((Constants.USERDEFAULTS .value(forKey: "token")) != nil){

        token = Constants.USERDEFAULTS.value(forKey: "token") as! String
    }
    else{
         token = ""
    }

    let headers = [
        "Authorization": "Bearer \(token)",
        "Accept": "application/json"
    ]


    let manager = Alamofire.SessionManager.default
    manager.session.configuration.timeoutIntervalForRequest = 120
    manager.request(url!, method: .post, parameters: params, headers: headers)
        .responseJSON
        {
            response in
            switch (response.result)
            {
            case .success:
                let jsonResponse = response.result.value as! NSDictionary
                print(jsonResponse)
                completion(jsonResponse)
                Utils().HideLoader()
            case .failure(let error):
                Utils().showAlert("Something went wrong")
                Utils().HideLoader()
                failure(error)
                break
        }
    }
}

回答by Ibrahim

Update to Swift 4.2

更新到 Swift 4.2

This code is based on pixel'sanswer, and is meant as an update for Swift 4.2

此代码基于像素的答案,旨在作为更新Swift 4.2

let bodyData = "key1=value&key2=value&key3=value"
request.httpBody = bodyData.data(using: .utf8)

回答by Mohit Tomar

 var post:NSString = "api=myposts&userid=\(uid)&page_no=0&limit_no=10"

    NSLog("PostData: %@",post);

    var url1:NSURL = NSURL(string: url)!

    var postData:NSData = post.dataUsingEncoding(NSASCIIStringEncoding)!

    var postLength:NSString = String( postData.length )

    var request:NSMutableURLRequest = NSMutableURLRequest(URL: url1)
    request.HTTPMethod = "POST"
    request.HTTPBody = postData
    request.setValue(postLength, forHTTPHeaderField: "Content-Length")
    request.setValue("application/x-www-form-urlencoded", forHTTPHeaderField: "Content-Type")
    request.setValue("application/json", forHTTPHeaderField: "Accept")


    var reponseError: NSError?
    var response: NSURLResponse?

    var urlData: NSData? = NSURLConnection.sendSynchronousRequest(request, returningResponse:&response, error:&reponseError)

    if ( urlData != nil ) {
        let res = response as NSHTTPURLResponse!;

        NSLog("Response code: %ld", res.statusCode);

        if (res.statusCode >= 200 && res.statusCode < 300)
        {
            var responseData:NSString  = NSString(data:urlData!, encoding:NSUTF8StringEncoding)!

            NSLog("Response ==> %@", responseData);

            var error: NSError?

            let jsonData:NSDictionary = NSJSONSerialization.JSONObjectWithData(urlData!, options:NSJSONReadingOptions.MutableContainers , error: &error) as NSDictionary


            let success:NSInteger = jsonData.valueForKey("error") as NSInteger

            //[jsonData[@"success"] integerValue];

            NSLog("Success: %ld", success);

            if(success == 0)
            {
                NSLog("Login SUCCESS");

                self.dataArr = jsonData.valueForKey("data") as NSMutableArray 
                self.table.reloadData()

            } else {

                NSLog("Login failed1");
            }

        } else {

            NSLog("Login failed2");

        }
    } else {

         NSLog("Login failed3");
    }

This will help you definitely

这绝对会帮助你