PHP 解码 JSON POST
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PHP decode JSON POST
提问by Chris
I"m trying to receive POSTdata in the form of JSON. I'm curling it as:
我正在尝试以POSTJSON 的形式接收数据。我将其卷曲为：
curl -v --header 'content-type:application/json' -X POST --data '{"content":"test content","friends":[\"38383\",\"38282\",\"38389\"],"newFriends":0,"expires":"5-20-2013","region":"35-28"}' http://testserver.com/wg/create.php?action=post
On the PHP side my code is:
在 PHP 方面，我的代码是：
$data = json_decode(file_get_contents('php://input'));
$content = $data->{'content'};
$friends = $data->{'friends'}; // JSON array of FB IDs
$newFriends = $data->{'newFriends'};
$expires = $data->{'expires'};
$region = $data->{'region'};
But even when I print_r ( $data)nothing gets returned to me. Is this the right way of processing a POSTwithout a form?
但即使我print_r ( $data)什么也得不到。这是处理POST没有表格的正确方法吗？
回答by MatsLindh
The JSON data you're submitting is not valid JSON.
您提交的 JSON 数据不是有效的 JSON。
When you use ' in your shell, it will not handle \" as you suspect.
当您在 shell 中使用 ' 时，它不会像您怀疑的那样处理 \"。
curl -v --header 'content-type:application/json' -X POST --data '{"content":"test content","friends": ["38383","38282","38389"],"newFriends":0,"expires":"5-20-2013","region":"35-28"}'
Works as expected.
按预期工作。
<?php
$foo = file_get_contents("php://input");
var_dump(json_decode($foo, true));
?>
Outputs:
输出：
array(5) {
["content"]=>
string(12) "test content"
["friends"]=>
array(3) {
[0]=>
string(5) "38383"
[1]=>
string(5) "38282"
[2]=>
string(5) "38389"
}
["newFriends"]=>
int(0)
["expires"]=>
string(9) "5-20-2013"
["region"]=>
string(5) "35-28"
}
