Python 如何仅打印出熊猫数据框的索引？
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How can I print out just the index of a pandas dataframe?
提问by Dan
I'm trying to make a table, and the way Pandas formats its indices is exactly what I'm looking for. That said, I don't want the actual data, and I can't figure out how to get Pandas to print out just the indices without the corresponding data.
我正在尝试制作一张表格，而 Pandas 格式化其索引的方式正是我正在寻找的。也就是说，我不想要实际数据，而且我不知道如何让 Pandas 只打印出没有相应数据的索引。
采纳答案by EdChum
You can access the index attribute of a df using .index:
您可以使用以下方法访问 df 的索引属性.index：
In [277]:
df = pd.DataFrame({'a':np.arange(10), 'b':np.random.randn(10)})
df
Out[277]:
a b
0 0 0.293422
1 1 -1.631018
2 2 0.065344
3 3 -0.417926
4 4 1.925325
5 5 0.167545
6 6 -0.988941
7 7 -0.277446
8 8 1.426912
9 9 -0.114189
In [278]:
df.index
Out[278]:
Int64Index([0, 1, 2, 3, 4, 5, 6, 7, 8, 9], dtype='int64')
回答by fixxxer
.index.tolist()is another function which you can get the index as a list:
.index.tolist()是另一个可以将索引作为列表获取的函数：
In [1391]: datasheet.head(20).index.tolist()
Out[1391]: [0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 16, 17, 18, 19]
回答by NILESH KUMAR
You can access the index attribute of a df using df.index[i]
您可以使用 df.index[i] 访问 df 的索引属性
>> import pandas as pd
>> import numpy as np
>> df = pd.DataFrame({'a':np.arange(5), 'b':np.random.randn(5)})
a b
0 0 1.088998
1 1 -1.381735
2 2 0.035058
3 3 -2.273023
4 4 1.345342
>> df.index[1] ## Second index
>> df.index[-1] ## Last index
>> for i in xrange(len(df)):print df.index[i] ## Using loop
...
0
1
2
3
4
