java 如何从 JSON 字符串获取值的所有 JSON 路径的列表？
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How do I get a list of all JSON paths to values from a JSON String?
提问by yak
My goal is to read a JSON file and understand the location of all the values, so that when I encounter that same JSON, I can easily read all the values. I am looking for a way to return a list containing all of the paths to each data value, in Jayway JsonPathformat.
我的目标是读取一个 JSON 文件并了解所有值的位置，这样当我遇到相同的 JSON 时，我可以轻松读取所有值。我正在寻找一种以Jayway JsonPath格式返回包含每个数据值的所有路径的列表的方法。
Example JSON:
示例 JSON：
{
"shopper": {
"Id": "4973860941232342",
"Context": {
"CollapseOrderItems": false,
"IsTest": false
}
},
"SelfIdentifiersData": {
"SelfIdentifierData": [
{
"SelfIdentifierType": {
"SelfIdentifierType": "111"
}
},
{
"SelfIdentifierType": {
"SelfIdentifierType": "2222"
}
}
]
}
}
Ideally I would like to take that JSON as a String and do something like this:
理想情况下，我想将该 JSON 作为字符串并执行以下操作：
String json = "{'shopper': {'Id': '4973860941232342', 'Context': {'CollapseOrderItems': false, 'IsTest': false } }, 'SelfIdentifiersData': {'SelfIdentifierData': [{'SelfIdentifierType': {'SelfIdentifierType': '111'} }, {'SelfIdentifierType': {'SelfIdentifierType': '2222'} } ] } }";
Configuration conf = Configuration.defaultConfiguration();
List<String> jsonPaths = JsonPath.using(conf).parse(json).read("$");
for (String path : jsonPaths) {
System.out.println(path);
}
This code would print this, which is the location of all values in the JSON:
此代码将打印此内容，即 JSON 中所有值的位置：
$.shopper.Id
$.shopper.Context.CollapseOrderItems
$.shopper.Context.IsTest
$.SelfIdentifiersData[0].SelfIdentifierData.SelfIdentifierType.SelfIdentifierType
$.SelfIdentifiersData[1].SelfIdentifierData.SelfIdentifierType.SelfIdentifierType
Then ideally, I would be able to take that list and parse the same JSON object to get each value present.
然后理想情况下，我将能够获取该列表并解析相同的 JSON 对象以获取每个值。
//after list is created
Object document = Configuration.defaultConfiguration().jsonProvider().parse(json);
for (String path : jsonPaths) {
Object value = JsonPath.read(document, path);
//do something
}
I am aware that I could get a Map that is a representation of the JSON file, but I am not sure that provides the same ease of access to retrieve all the values. If there is a easy way to do with JSONPath, that would be great, otherwise any other approaches are welcome.
我知道我可以获得一个代表 JSON 文件的 Map，但我不确定它是否提供了检索所有值的相同易用性。如果有一种简单的方法来处理 JSONPath，那就太好了，否则欢迎使用任何其他方法。
回答by yak
I came up with a solution, sharing in case anyone else is looking for the same thing:
我想出了一个解决方案，分享一下，以防其他人正在寻找同样的事情：
public class JsonParser {
private List<String> pathList;
private String json;
public JsonParser(String json) {
this.json = json;
this.pathList = new ArrayList<String>();
setJsonPaths(json);
}
public List<String> getPathList() {
return this.pathList;
}
private void setJsonPaths(String json) {
this.pathList = new ArrayList<String>();
JSONObject object = new JSONObject(json);
String jsonPath = "$";
if(json != JSONObject.NULL) {
readObject(object, jsonPath);
}
}
private void readObject(JSONObject object, String jsonPath) {
Iterator<String> keysItr = object.keys();
String parentPath = jsonPath;
while(keysItr.hasNext()) {
String key = keysItr.next();
Object value = object.get(key);
jsonPath = parentPath + "." + key;
if(value instanceof JSONArray) {
readArray((JSONArray) value, jsonPath);
}
else if(value instanceof JSONObject) {
readObject((JSONObject) value, jsonPath);
} else { // is a value
this.pathList.add(jsonPath);
}
}
}
private void readArray(JSONArray array, String jsonPath) {
String parentPath = jsonPath;
for(int i = 0; i < array.length(); i++) {
Object value = array.get(i);
jsonPath = parentPath + "[" + i + "]";
if(value instanceof JSONArray) {
readArray((JSONArray) value, jsonPath);
} else if(value instanceof JSONObject) {
readObject((JSONObject) value, jsonPath);
} else { // is a value
this.pathList.add(jsonPath);
}
}
}
}
回答by Swapnil Jaju
Refer to this utility : https://github.com/wnameless/json-flattenerPerfect answer to your requirement. Provides Flattened map and Flattened strings for complex json strings. I am not the author of this but have used it successfully for my usecase.
请参阅此实用程序：https: //github.com/wnameless/json-flattener完美满足您的要求。为复杂的 json 字符串提供扁平化的地图和扁平化的字符串。我不是本文的作者，但已成功将其用于我的用例。
