bash 回声换行抑制
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echo newline suppression
提问by Happy Mittal
Why doesn't $echo '-n'
write -n
on terminal although -n
is written within single quotes ?
为什么不$echo '-n'
写-n
在终端虽然-n
写在单引号内?
回答by laalto
Because the quotes are processed by the shell and the echo
command receives plain -n
. If you want to echo -n
, you can e.g. printf '%s\n' -n
因为引号是由 shell 处理的,并且echo
命令接收到普通的-n
. 如果你想回声-n
,你可以例如printf '%s\n' -n
回答by Erik Bitemo
I found that the following just works in bash:
我发现以下内容仅适用于 bash:
echo -n PRINT_THIS
So, you should put -n the first place.
所以,你应该把 -n 放在第一位。
回答by ghostdog74
you should try to use the more portable printf
as far as possible.
你应该尽量使用更便携的printf
。
回答by kennytm
You could try
你可以试试
echo -e '5n'
回答by user unknown
Not quiete there:
那里不安静:
echo -e 'a-n\b\b\b '
-n
surprisingly this works:
令人惊讶的是,这有效:
echo -e '-n\b'
-n
and here a solution I can explain:
在这里我可以解释一个解决方案:
echo "foobar" | sed 's/.*/-n/'
-n
回答by Pointy
The quotes don't help because ... ugh, it's hard to explain. The shell strips the quotes off before the "echo" command itself is evaluated, so by that time they don't matter.
引号没有帮助,因为......呃,很难解释。shell 在“echo”命令本身被评估之前去掉引号,所以到那时它们无关紧要。
Try this:
尝试这个:
echo - -n
That's not documented as working (I'm running Ubuntu Linux), but echo
is almost certainly a built-in to whatever shell you're using, so the man page is questionable anyway. It does work for me. (I'm running zsh
because I'm really suave and sophisticated).
这并没有记录在案(我正在运行 Ubuntu Linux),但echo
几乎可以肯定它是您正在使用的任何 shell 的内置文件,因此手册页无论如何都是有问题的。它对我有用。(我跑步zsh
是因为我真的很文雅又老练)。
edit: well it seems that the bash
builtin edit
doesn't behave that way. I don't know what to suggest; this:
编辑:好吧,似乎bash
内置edit
函数不会那样做。我不知道该建议什么;这个:
echo '' -n
will give you "-n" preceded by a space, which (depending on what you're doing) might be OK.
会给你一个空格前面的“-n”,这(取决于你在做什么)可能没问题。