Linux/Unix Bash 脚本如何知道自己的 PID？
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How does a Linux/Unix Bash script know its own PID?
提问by Debugger
I have a script in Bash called Script.sh, and it needs to know its own PID (i.e. I need to get PID inside the Script.sh )
我在 Bash 中有一个名为 的脚本Script.sh，它需要知道自己的 PID（即我需要在 Script.sh 中获取 PID）
Any idea how to do this ?
知道如何做到这一点吗？
回答by Paul Tomblin
The variable '$$' contains the PID.
变量“$$”包含PID。
回答by tvanfosson
use $BASHPIDor $$
使用$BASHPID或$$
See the manualfor more information, including differences between the two.
有关更多信息，包括两者之间的差异，请参阅手册。
TL;DRTFM
TL;DRTFM
$$Expands to the process ID of the shell.- In a
()subshell, it expands to the process ID of the invoking shell, not the subshell.
- In a
$BASHPIDExpands to the process ID of the current Bash process.- In a
()subshell, it expands to the process ID of the subshell
- In a
$$扩展到 shell 的进程 ID。- 在
()子shell 中，它扩展为调用shell 的进程ID，而不是子shell。
- 在
$BASHPID扩展为当前 Bash 进程的进程 ID。- 在
()子shell中，它扩展为子shell的进程ID
- 在
回答by Paused until further notice.
In addition to the example given in the Advanced Bash Scripting Guidereferenced by Jefromi, these examples show how pipes create subshells:
除了Jefromi引用的Advanced Bash Scripting Guide 中给出的示例之外，这些示例展示了管道如何创建子外壳：
$ echo $$ $BASHPID | cat -
11656 31528
$ echo $$ $BASHPID
11656 11656
$ echo $$ | while read line; do echo $line $$ $BASHPID; done
11656 11656 31497
$ while read line; do echo $line $$ $BASHPID; done <<< $$
11656 11656 11656
回答by neo
The PID is stored in $$.
PID 存储在$$.
Example: kill -9 $$will kill the shell instance it is called from.
示例：kill -9 $$将终止调用它的 shell 实例。
回答by Klaus Byskov Pedersen
You can use the $$variable.
您可以使用该$$变量。
回答by Joakim J. Rapp
If the process is a child process and $BASHPID is not set, it is possible to query the ppid of a created child process of the running process. It might be a bit ugly, but it works. Example:
如果进程是子进程并且没有设置$BASHPID，则可以查询正在运行的进程创建的子进程的ppid。它可能有点难看，但它有效。例子：
sleep 1 &
mypid=$(ps -o ppid= -p "$!")
