java 从 <li> 下拉列表中选择值 - Selenium
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Selecting value from <li> dropdown - Selenium
提问by NewCoder888
I'm trying to select a value from a small dropdown that appears to be a "ul" Here's what I see in Firebug:
我正在尝试从一个看起来像“ul”的小下拉列表中选择一个值，这是我在 Firebug 中看到的：
<button class="btn btn-default dropdown-toggle" aria-expanded="true" aria-haspopup="true" data-toggle="dropdown" type="button">
<ul class="dropdown-menu">
<li>
<a href="javascript:void(0)">1</a>
</li>
<li>
<a href="javascript:void(0)">2</a>
</li>
<li>
<a href="javascript:void(0)">3</a>
Here's what I have so far, in Java:
到目前为止，这是我在 Java 中所做的：
public void selectPhoneType(String option)
{
driver.findElement(By.className("caret")).click();
new WebDriverWait(driver, 5).until(ExpectedConditions.visibilityOfElementLocated(By.className("dropdown-menu")));
WebElement element = driver.findElement()
}
Let's say I wanted to select/click on option "1". How would I complete my code? I haven't worked with "li" too much so I tried using a select, which obviously didnt work. Any help would be appreciated! Thanks
假设我想选择/单击选项 "1"。我将如何完成我的代码？我没有过多地使用“li”，所以我尝试使用选择，这显然不起作用。任何帮助，将不胜感激！谢谢
回答by misterjake
Try something like this:
尝试这样的事情：
public void selectPhoneType(String option) {
// Open the dropdown so the options are visible
driver.findElement(By.className("dropdown-menu")).click();
// Get all of the options
List<WebElement> options = driver.findElements(By.xpath("//ul[@class='dropdown-menu']/li"));
// Loop through the options and select the one that matches
for (WebElement opt : options) {
if (opt.getText().equals(option)) {
opt.click();
return;
}
}
throw new NoSuchElementException("Can't find " + option + " in dropdown");
}
Note: Selenium's Select() won't work here because your list is not under a 'select' tag.
注意：Selenium 的 Select() 在这里不起作用，因为您的列表不在“选择”标签下。
回答by Роман Гуйван
Based on how it's selected in the application you either should simulate mouse click with element.click()or simulate keydown/keyup event with element.sendKeys(Keys.ENTER);Also be aware that touch events may handle differently by your application (click may not work)
Here's a similar question
根据它在应用程序中的选择方式，您应该使用模拟鼠标单击element.click()或模拟 keydown/keyup 事件element.sendKeys(Keys.ENTER);另外请注意，您的应用程序可能会以不同方式处理触摸事件（单击可能不起作用）
这是一个类似的问题
回答by Leon Barkan
driver.FindElement(By.XPath("//ul[@class='dropdown-menu']/li/a")).Click();
回答by Leon Barkan
Another approach which parameterizes the selector.
另一种参数化选择器的方法。
This returns all 3 options:
这将返回所有 3 个选项：
$$("ul.dropdown-menu>li:eq a")
This adds a parameter to select which in the list you want:
这将添加一个参数以选择您想要的列表中的哪个：
$$("ul.dropdown-menu>li:nth-child(1) a")
Then you can map for your tests the child number and pass it into the selector:
然后，您可以为您的测试映射子编号并将其传递给选择器：
1 = whatever
2 = whatever
3 = whatever
public void By someDroplist(String selection)
{
return By.cssSelector("ul.dropdown-menu>li:nth-child(" + selection + ") a");
}
