使用 Python 创建二维坐标

Use Python to create 2D coordinate

提问by Jianli Cheng

I am truly a novice in Python. Now, I am doing a project which involves creating a list of 2D coordinates. The coordinates should be uniformly placed, using a square grid (10*10), like(0,0)(0,1)(0,2)(0,3)...(0,10)(1,0)(1,2)(1,3)...(2,0)(2,1)(2,2)...(10,10).

我真的是 Python 的新手。现在，我正在做一个涉及创建二维坐标列表的项目。坐标应均匀放置，使用方形网格 (10*10)，如 (0,0)(0,1)(0,2)(0,3)...(0,10)(1,0 )(1,2)(1,3)...(2,0)(2,1)(2,2)...(10,10)。

Here is my code:

这是我的代码：

coordinate = []
x = 0
y = 0
while y < 10:
    while x < 10:
        coordinate.append((x,y))
        x += 1
    coordinate.append((x,y))
    y += 1
print(coordinate)

But I can only get: [(0, 0), (1, 0), (2, 0), (3, 0), (4, 0), (5, 0), (6, 0), (7, 0), (8, 0), (9, 0), (10, 0), (10, 1), (10, 2), (10, 3), (10, 4), (10, 5), (10, 6), (10, 7), (10, 8), (10, 9)]

但我只能得到：[(0, 0), (1, 0), (2, 0), (3, 0), (4, 0), (5, 0), (6, 0), ( 7, 0), (8, 0), (9, 0), (10, 0), (10, 1), (10, 2), (10, 3), (10, 4), (10, 5), (10, 6), (10, 7), (10, 8), (10, 9)]

How can I rewrite my code to get all the points?

如何重写我的代码以获得所有积分？

回答by Ashwini Chaudhary

Use itertools.product:

使用itertools.product：

>>> from itertools import product
>>> list(product(range(11), repeat=2))
[(0, 0), (0, 1), (0, 2), (0, 3), (0, 4), (0, 5), (0, 6), (0, 7), (0, 8), (0, 9), (0, 10), (1, 0), (1, 1), (1, 2), (1, 3), (1, 4), (1, 5), (1, 6), (1, 7), (1, 8), (1, 9), (1, 10), (2, 0), (2, 1), (2, 2), (2, 3), (2, 4), (2, 5), (2, 6), (2, 7), (2, 8), (2, 9), (2, 10), (3, 0), (3, 1), (3, 2), (3, 3), (3, 4), (3, 5), (3, 6), (3, 7), (3, 8), (3, 9), (3, 10), (4, 0), (4, 1), (4, 2), (4, 3), (4, 4), (4, 5), (4, 6), (4, 7), (4, 8), (4, 9), (4, 10), (5, 0), (5, 1), (5, 2), (5, 3), (5, 4), (5, 5), (5, 6), (5, 7), (5, 8), (5, 9), (5, 10), (6, 0), (6, 1), (6, 2), (6, 3), (6, 4), (6, 5), (6, 6), (6, 7), (6, 8), (6, 9), (6, 10), (7, 0), (7, 1), (7, 2), (7, 3), (7, 4), (7, 5), (7, 6), (7, 7), (7, 8), (7, 9), (7, 10), (8, 0), (8, 1), (8, 2), (8, 3), (8, 4), (8, 5), (8, 6), (8, 7), (8, 8), (8, 9), (8, 10), (9, 0), (9, 1), (9, 2), (9, 3), (9, 4), (9, 5), (9, 6), (9, 7), (9, 8), (9, 9), (9, 10), (10, 0), (10, 1), (10, 2), (10, 3), (10, 4), (10, 5), (10, 6), (10, 7), (10, 8), (10, 9), (10, 10)]

The above code is equivalent to this nested list comprehension:

上面的代码等价于这个嵌套列表推导式：

>>> [(x, y) for x in range(11) for y in range(11)]
[(0, 0), (0, 1), (0, 2), (0, 3), (0, 4), (0, 5), (0, 6), (0, 7), (0, 8), (0, 9), (0, 10), (1, 0), (1, 1), (1, 2), (1, 3), (1, 4), (1, 5), (1, 6), (1, 7), (1, 8), (1, 9), (1, 10), (2, 0), (2, 1), (2, 2), (2, 3), (2, 4), (2, 5), (2, 6), (2, 7), (2, 8), (2, 9), (2, 10), (3, 0), (3, 1), (3, 2), (3, 3), (3, 4), (3, 5), (3, 6), (3, 7), (3, 8), (3, 9), (3, 10), (4, 0), (4, 1), (4, 2), (4, 3), (4, 4), (4, 5), (4, 6), (4, 7), (4, 8), (4, 9), (4, 10), (5, 0), (5, 1), (5, 2), (5, 3), (5, 4), (5, 5), (5, 6), (5, 7), (5, 8), (5, 9), (5, 10), (6, 0), (6, 1), (6, 2), (6, 3), (6, 4), (6, 5), (6, 6), (6, 7), (6, 8), (6, 9), (6, 10), (7, 0), (7, 1), (7, 2), (7, 3), (7, 4), (7, 5), (7, 6), (7, 7), (7, 8), (7, 9), (7, 10), (8, 0), (8, 1), (8, 2), (8, 3), (8, 4), (8, 5), (8, 6), (8, 7), (8, 8), (8, 9), (8, 10), (9, 0), (9, 1), (9, 2), (9, 3), (9, 4), (9, 5), (9, 6), (9, 7), (9, 8), (9, 9), (9, 10), (10, 0), (10, 1), (10, 2), (10, 3), (10, 4), (10, 5), (10, 6), (10, 7), (10, 8), (10, 9), (10, 10)]

回答by Shashank

Use a forloop. It lets you iterate over things called "iterators". rangeis a built-in function which returns an iterator from its starting argument (first argument) inclusive. up to its ending argument (second argument) non-inclusive. Thus range(0,11)will return 0,1,2,...,10.

使用for循环。它允许您迭代称为“迭代器”的东西。range是一个内置函数，它从它的起始参数（第一个参数）返回一个迭代器。直到其结束参数（第二个参数）不包括在内。因此range(0,11)将返回 0,1,2,...,10。

coordinate = []
for y in range(0, 11):
    for x in range(0, 11):
        coordinate.append((x,y))
print(coordinate)

For more information on forloops in Python, check out the official wiki page.

有关forPython 中循环的更多信息，请查看官方 wiki 页面。

回答by Akavall

from itertools import product

x = (0, 1, 2)

test = product(x, x)

Result:

结果：

>>> for ele in test:
...     print ele
... 
(0, 0)
(0, 1)
(0, 2)
(1, 0)
(1, 1)
(1, 2)
(2, 0)
(2, 1)
(2, 2)

Note that testis a generator, so you probably would want to use list(test).

请注意，这test是一个生成器，因此您可能想要使用list(test).

回答by erewok

It's common to use a couple of for-loops to achieve this:

通常使用几个 for 循环来实现这一点：

coordinates = []

for x in range(11):
  for y in range(11):
    coordinates.append((x, y))

It's also common to simplify this by flattening it into a list comprehension:

通过将其扁平化为列表理解来简化它也很常见：

coordinates = [(x,y) for x in range(11) for y in range(11)]

回答by Pavel Anossov

To actually answer your question, you forgot to reset xback to zero after the first run through x=0..9:

要实际回答您的问题，您x在第一次运行 x=0..9 后忘记重置为零：

coordinate = []

y = 0
while y < 10:
    x = 0
    while x < 10:
        coordinate.append((x,y))
        x += 1
    coordinate.append((x,y))
    y += 1
print(coordinate)

Feel free to use all other variants, of course.

当然，您可以随意使用所有其他变体。