pandas 熊猫直方图：将每列的直方图绘制为大图的子图
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pandas histogram: plot histogram for each column as subplot of a big figure
提问by Edamame
I am using the following code, trying to plot the histogram of every column of a my pandas data frame df_in as subplot of a big figure.
我正在使用以下代码，尝试将我的 Pandas 数据框 df_in 的每一列的直方图绘制为大图的子图。
%matplotlib notebook
from itertools import combinations
import matplotlib.pyplot as plt
fig, axes = plt.subplots(len(df_in.columns) // 3, 3, figsize=(12, 48))
for x in df_in.columns:
df_in.hist(column = x, bins = 100)
fig.tight_layout()
However, the histogram didn't show in the subplot. Any one knows what I missed? Thanks!
但是，直方图没有显示在子图中。有谁知道我错过了什么？谢谢！
回答by Pascal Antoniou
I can't comment burhan's answer because I don't have enough reputation points. The problem with his answer is that axesisn't one-dimensional, it contains axes triads, so it needs to be unrolled:
我无法评论 burhan 的回答，因为我没有足够的声望点。他的答案的问题在于axes它不是一维的，它包含轴三元组，因此需要展开：
%matplotlib notebook
from itertools import combinations
import matplotlib.pyplot as plt
fig, axes = plt.subplots(len(df_in.columns)//3, 3, figsize=(12, 48))
i = 0
for triaxis in axes:
for axis in triaxis:
df_in.hist(column = df_in.columns[i], bins = 100, ax=axis)
i = i+1
回答by burhan
You need to specify which axis you are plotting to. This should work:
您需要指定要绘制到哪个轴。这应该有效：
fig, axes = plt.subplots(len(df_in.columns)//3, 3, figsize=(12, 48))
for col, axis in zip(df_in.columns, axes):
df_in.hist(column = col, bins = 100, ax=axis)
