是否可以使用 java FileSystem 创建新的 zip 文件？
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Is it possible to create a NEW zip file using the java FileSystem?
提问by Ordiel
I've successfully modified the contents of a (existing) zip file using the FileSystemprovided by java 7, but when I tried to create a NEW zip file by this method it fails, with the error message that says: "zip END header not found", it is logical because of the way I'm doing it, first I create the file (Files.createFile) which is a completely empty file, and then I try to access to its file system , and since the file is empty its impossible to find any header inside the zip, my question isis there any way to create a new zip file completely empty using this method?; the hack that I've considered is adding an empty new ZipEntryto a the zip file and then using that new empty file to crate the file system based on it, but i really want to think that the guys of oracle implemented a better (easier) way to do this with nio and the filesystems...
我已经使用FileSystemjava 7 提供的成功修改了（现有）zip 文件的内容，但是当我尝试通过这种方法创建一个新的 zip 文件时，它失败了，错误消息是："zip END header not found"，这是合乎逻辑的，因为我这样做的方式是，首先我创建了Files.createFile一个完全空文件的文件 ( )，然后我尝试访问它的文件系统，由于该文件是空的，因此无法在 zip 中找到任何标题，我的问题是有没有办法使用这种方法创建一个完全空的新 zip 文件？我考虑过的黑客是添加一个空的新ZipEntry到一个 zip 文件，然后使用这个新的空文件来创建基于它的文件系统，但我真的想认为 oracle 的人用 nio 和文件系统实现了一种更好（更简单）的方法来做到这一点......
this is my code (the error appears when creating the file system):
这是我的代码（创建文件系统时出现错误）：
if (!zipLocation.toFile().exists()) {
if (creatingFile) {
Files.createFile(zipLocation);
}else {
return false;
}
} else if (zipLocation.toFile().exists() && !replacing) {
return false;
}
final FileSystem fs = FileSystems.newFileSystem(zipLocation, null);
.
.
.
zipLocationis a Path
creatingFileis a boolean
zipLocation是一个路径
creatingFile是一个布尔值
ANSWER:in my particular case the answer given didn't work appropriately because of the spaces in the path, therefore i have to do it the way i didn't want to:
答案：在我的特殊情况下，由于路径中的空格，给出的答案无法正常工作，因此我必须按照我不想的方式进行：
Files.createFile(zipLocation);
ZipOutputStream out = new ZipOutputStream(
new FileOutputStream(zipLocation.toFile()));
out.putNextEntry(new ZipEntry(""));
out.closeEntry();
out.close();
it does not mean that the given answer is wrong, it just didn't work for my particular case
这并不意味着给出的答案是错误的，只是对我的特定情况不起作用
回答by Carlo Pellegrini
As described in The Oracle Site:
public static void createZip(Path zipLocation, Path toBeAdded, String internalPath) throws Throwable {
Map<String, String> env = new HashMap<String, String>();
// check if file exists
env.put("create", String.valueOf(Files.notExists(zipLocation)));
// use a Zip filesystem URI
URI fileUri = zipLocation.toUri(); // here
URI zipUri = new URI("jar:" + fileUri.getScheme(), fileUri.getPath(), null);
System.out.println(zipUri);
// URI uri = URI.create("jar:file:"+zipLocation); // here creates the
// zip
// try with resource
try (FileSystem zipfs = FileSystems.newFileSystem(zipUri, env)) {
// Create internal path in the zipfs
Path internalTargetPath = zipfs.getPath(internalPath);
// Create parent directory
Files.createDirectories(internalTargetPath.getParent());
// copy a file into the zip file
Files.copy(toBeAdded, internalTargetPath, StandardCopyOption.REPLACE_EXISTING);
}
}
public static void main(String[] args) throws Throwable {
Path zipLocation = FileSystems.getDefault().getPath("a.zip").toAbsolutePath();
Path toBeAdded = FileSystems.getDefault().getPath("a.txt").toAbsolutePath();
createZip(zipLocation, toBeAdded, "aa/aa.txt");
}
