bash 使用 awk 和 df（无磁盘）仅显示挂载名称和使用的空间
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Using awk and df (disk free) to show only mount name and space used
提问by Rick
What would be the correct CL sequence to execute a df -hand only print out the mount name and used space (percentage)? I'm trying to do a scripted report for our servers.
执行 adf -h并仅打印出安装名称和已用空间（百分比）的正确 CL 序列是什么？我正在尝试为我们的服务器编写脚本报告。
I tried
我试过
df -h | awk '{print $1 $4}'
df -h | awk '{print $1 $4}'
which spits out
吐出来的
$df -h | awk '{print }'
FilesystemAvail
/dev/sda164G
udev3.9G
tmpfs1.6G
none5.0M
none3.9G
none100M
/home/richard/.Private64G
How would you change this to add spacing? Am I selecting the right columns?
你会如何改变它以增加间距？我是否选择了正确的列？
回答by Ansgar Wiechers
Try this:
尝试这个：
df -h | awk '{if ( != "Filesystem") print " " }'
Or just
要不就
df -h | awk '{print " " }'
if you want to keep the headers.
如果你想保留标题。
回答by perreal
You are almost there:
你快到了：
df -h | awk 'NR>1{print , }'
回答by janm
The issues with your code are what input to process, and how to format the output.
您的代码的问题是要处理什么输入，以及如何格式化输出。
As an example, this awk selects records that have a % symbol at the end of field five, and put a space between the two output fields.
例如，此 awk 选择在字段 5 末尾具有 % 符号的记录，并在两个输出字段之间放置一个空格。
df -h | awk ' ~ /\%$/ {print " " }'
Everything else is just refining those two things.
其他的都只是提炼这两点而已。
