bash 打印 unicode 字符
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Print unicode character
提问by Steven Penny
With Bash, you can use printfwith hex codes
使用 Bash，您可以使用printf十六进制代码
\xHH byte with hexadecimal value HH (1 to 2 digits)
\uHHHH Unicode (ISO/IEC 10646) character with hex value HHHH (4 digits)
example
例子
$ printf '\x26'
&
However the Unicode example does not print as expected
但是 Unicode 示例没有按预期打印
$ printf '\u0026'
\u0026
My Bash version
我的 Bash 版本
$ echo $BASH_VERSION
4.1.10(4)-release
采纳答案by chepner
What version of bashare you using (echo $BASH_VERSIONor bash --version)? The Unicode escapes work in bash4.2, but not 3.2.48. I suspect support was added in bash4.0.
bash您使用的是哪个版本的(echo $BASH_VERSION或bash --version)？Unicode 转义在bash4.2 中有效，但在 3.2.48 中无效。我怀疑在bash4.0中添加了支持。
Update: I can confirm it does not work in bash4.1.2. This functionality appears to have been added in bash4.2.
更新：我可以确认它在bash4.1.2 中不起作用。此功能似乎已在bash4.2 中添加。
Update 2: From the release notes for bash 4.2:
d.
$'...',echo, andprintfunderstand\uXXXXand\UXXXXXXXXescape sequences.
d.
$'...',echo, 以及printf理解\uXXXX和\UXXXXXXXX转义序列。
